In the given you wrote -2, whereas it should be -2i
z = a + bi and in trigo form | z |.(cos Ф + i.sin Ф).
z = 0 -2i → | z |.(cos Ф + i.sin Ф)
Now let's calculate z:
z² = a²+b² → z² = 0² (-2.i)² → z = -2(i)² →z= -2(-1) → z = |2|
tan Ф = b/a = -2/0 → tan Ф → - ∞ ↔ Ф = -90° or Ф = 270°
then the - 2 I ↔ |2|(cos 270° + i.sin 270°)
Answer:<u> 9.42 inches</u>, 3π in terms of pi
Step-by-step explanation:
A full circle is 360 degrees, so if the segment has an arc of 120 degrees, it is 1/3 of a regular circle.
To find the area of a circle, we use the equation A = πr^2. In this case, we will divide the equation by 3 because we are only finding 1/ of a circle. So, our equation will be A = (πr^2)/3.
Using 3.14 for π:
A = (πr^2)/3.
A = (π3^2)/3
A = (π9)/3
A = 3π
A = 9.42
Answer:
The angles are 110, 110 and 140
Step-by-step explanation:
Let the equal angles be x.
So we have angles x, x and another third one
Now, the other third angle is 30 degrees larger than x, this means that the other third angle is 30 + x
Since they are angles at a point, adding the three together will make or give 360.
Thus,
x + x + x + 30 = 360
3x + 30 = 360
3x = 360-30
3x = 330
x = 330/3
x = 110
So the other third angle is 110 + 30 = 140
So the angles are 110, 110 and 140
We can use the points in either order and you will still get the same slope. I usually solve in order that is given. So the first coordinates I label (x1,y1) and the second is (x2,y2).
Slope=m=(y2-y1)/(x2-x1)
m=(9-5)/(3-1)=4/2=2
Slope is 2.
