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trapecia [35]
3 years ago
13

What is 78 with an exponent of 1 million?

Mathematics
2 answers:
madam [21]3 years ago
8 0
Literally Infinity :P i dont know what number that would be
mafiozo [28]3 years ago
6 0
78*10^6 = 7.8*10*10^6 = 7.8*10^7
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Help please :) Whoever helps and gets answer correct gets Brainliest!
Keith_Richards [23]

Answer:

1/8 is the slope

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which of the following is located over the center of the base of a regular pyramid
kenny6666 [7]

Vertex is located over the center of the base of a regular pyramid.

<h3>What is Vertex Angle?</h3>

Vertex angle is defined as the angle formed by two lines or rays that intersect at a point. These two rays make the sides of the angle.

Here,  Vertex is the point which is located over the center of the base of a regular pyramid.

Learn more about Vertex angle from:

brainly.com/question/2028172

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5 0
2 years ago
Rewrite x + 1 = 3 in terms of y if x = y^2 + 1.
ExtremeBDS [4]
ANSWER:
(y^2+1)+1=3

Hope it helps u! :)
3 0
3 years ago
The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times t
alexdok [17]
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)

The above three expressions could be used to represent the numbers.

Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44

x = 11, y = 7, z = 44.
3 0
3 years ago
Read 2 more answers
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
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