15 is 3 times 5. The point (5, 0) is dilated to the point (15, 0) by using a factor of
K = 3.
Photo-math take a picture of your problem and it will give you your answer
Answer:
1st option
Step-by-step explanation:
To find the difference of the given matrices, we just need to subtract the corresponding elements of the two matrices as shown below:
![\left[\begin{array}{cc}-4&8\\3&12\end{array}\right] -\left[\begin{array}{cc}2&1\\-14&15\end{array}\right] \\\\ \\ =\left[\begin{array}{cc}-4-2&8-1\\3-(-14)&12-15\end{array}\right]\\\\ \\ =\left[\begin{array}{cc}-6&7\\17&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%268%5C%5C3%2612%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C-14%2615%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%20%5C%5C%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4-2%268-1%5C%5C3-%28-14%29%2612-15%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%20%5C%5C%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%267%5C%5C17%26-3%5Cend%7Barray%7D%5Cright%5D)
Thus, 1st option gives the correct answer
Let us assume that the number of beige tiles bought by Susan = B
Number of red tiles bought by Susan = R
Number of navy-blue tiles bought by Susan =N
Number of tiles bought altogether = 435
Now from the given question we know:
Number of red tiles bought is 25 more than the number of beige tiles.
So
R = 25 + B
Number of navy blue tiles bought is 3 times that of the number of beige tile bought
So
N = 3B
We already know that the total number of tiles bought is 435
Hence
B + R + N = 435
B + (25 + B) + 3B = 435
5B + 25 = 435
5B = 435 -25
5B = 410
B = 82
R = 25 + B
= 25 + 82
= 107
N = 3B
= 3 * 82
= 246
So the number of Beige tiles bought by Susan = 82
The number of red tiles bought by Susan = 107
The number of navy-blue tiles bought by Susan = 246
