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Zigmanuir [339]
3 years ago
14

Anna is in a cave 39 feet below the cave entrance. She descends 19 feet, then ascends 25 feet. Find her new position relative to

the cave entrance.
Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

-40-13=-53

-53+18=-35

35 feet below the cave entrance

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Evaluate the expression <br> 5.4+ab, if a = 4 and b = 8
dsp73

Answer:

37.4

Step-by-step explanation:

a = 4 and b = 8

change the equation

5.4 + (4) (8)

use P.E.M.D.A.S. and multiply

4*8 = 32

add

5.4 + 32 = 37.4

7 0
3 years ago
Use fundamental theorem of calculus to find derivative of the function LOOK AT PHOTO
kykrilka [37]

Let c > 0. Then split the integral at t = c to write

f(x) = \displaystyle \int_{\ln(x)}^{\frac1x} (t + \sin(t)) \, dt = \int_c^{\frac1x} (t + \sin(t)) \, dt - \int_c^{\ln(x)} (t + \sin(t)) \, dt

By the FTC, the derivative is

\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}

8 0
2 years ago
What is the approximate volume of a cylinder with a radius of 8 cm and height of 5 cm?
lutik1710 [3]
Rounded up, the answer is 395 centimeters sq.
3 0
3 years ago
Read 2 more answers
A cable company wants to provide cell phone service for residents on an island. The function for the cost of laying the cable fr
laila [671]

Answer:

C) domain: all real numbers greater than or equal to 0

range: all real numbers greater than or equal to 13,000

Step-by-step explanation:

We have, the function for the cost of laying cable is given by,

c(x)= 6500\sqrt{x^2+4}, where x is the length of the cable (in feet).

As, 'x' represents the length of the cable.

We have that, the value of x cannot be negative.

So, x ≥ 0.

Since, the domain of c(x)= 6500\sqrt{x^2+4} is the set of points where x^2+4\geq 0 and we have that x ≥ 0.

Thus, the domain is 'Set of all real numbers greater than or equal to 0'.

Now, we substitute x= 0 in c(x)= 6500\sqrt{x^2+4}.

i.e. c(0)= 6500\sqrt{0^2+4}

i.e. c(0)= 6500\sqrt{4}

i.e. c(0)= 6500\times 2

i.e. c(0) = 13000.

So, we get that the vertex point of the function is (0,13000).

Thus, the range is 'All real numbers greater than or equal to 13,000'.

5 0
3 years ago
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Could someone help me??
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