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GenaCL600 [577]
3 years ago
10

Is (1, 4) a solution to the equation y = 7x?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

not a solution

Step-by-step explanation:

Substitute the point into the equation and see if it is true

y = 7x

4 = 7*1

4 = 7

This is not true so it is not a solution

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If it costs $0.15 per square inch for the cardboard label, then what is the cost for plan B?
IceJOKER [234]

Answer:

a box of plan B cost roughly $50.00

it is pretty expensive but you don't need an I.D.

Step-by-step explanation:

6 0
3 years ago
Logarithms:
WITCHER [35]

Answer:

  • A) k = 18.75
  • B) R(0.8) = 161419
  • C) R(0.3) = 275

Step-by-step explanation:

<u>Given expression</u>

  • R(x) = 6*e^(kx)

A) <u>Given</u>

  • x = 0.04
  • R = 10

<u>Solving for k</u>

  • 10 = 6*e^(0.04k)
  • e^(0.04k) = 10/6
  • ln (e^0.04k) = ln (1.6666)
  • 0.04k = 0.51
  • k = 0.51/0.04
  • k = 12.75

B) <u>Given</u>

  • x = 0.8
  • R= ?

<u>The value of R(0.8) is:</u>

  • R(0.8) =
  • 6*e^(0.8*12.75) =
  • 6*e^(10.2) =
  • 161419  rounded

C) <u>Given</u>

  • x = 0.3
  • R = ?

<u>The value of R(0.3) is:</u>

  • R(0.3) =
  • 6*e^(0.3*12.75) =
  • 6*e^(3.825) =
  • 275 rounded
4 0
3 years ago
Esther is pregnant and preparing for the birth of her first baby. In college, she ran up a large credit card bill and is still t
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5 0
4 years ago
Someone help please?
disa [49]
There is the answer my guy it’s a picture

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4 0
3 years ago
A shipping container shaped like a rectangular prism must have a maximum volume of 10 cubic yards. If the container is 2 1/2 yar
denpristay [2]

Answer:

1\frac{1}{7} yards

Step-by-step explanation:

The maximum volume the shipping container can have is 10 cubic yards.

The volume of a rectangular prism is given as:

V = L * W * H

where L is length, W is width and H is height.

To find the maximum height of the container, make H the subject of formula:

H = \frac{V}{L * W}

We have been given the length and width of the container as 2 1/2 yards and 3 1/2 yards respectively.

Hence, the maximum height is:

H = \frac{10}{2\frac{1}{2} * 3\frac{1}{2} } \\\\H = \frac{10}{\frac{5}{2} * \frac{7}{2} }

H = \frac{10}{\frac{35}{4} } \\\\H = \frac{10 * 4}{35} \\\\H = \frac{40}{35} = \frac{8}{7} = 1\frac{1}{7}

The maximum height of the container is 1\frac{1}{7} yards.

7 0
3 years ago
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