Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
I think the answer is ∆ BLG~=∆PFX.
Step-by-step explanation:
Since x represents the year, year 15 will be 15 years.
Plug in "15" as your "x"
y = -2(15)^2 + 36(15) + 6
15^2 = 225 (Exponents come before multiplication)
y = -2(225) + 36(15) + 6
y = -450 + 540 + 6
y = 90 + 6
y = 96
<em>The answer is B</em>
The mean is the best measure to summarise the scores.
Answer: A
Step-by-step explanation:
because i did a quiz with the same and i got it right