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Bingel [31]
3 years ago
14

Zero is a solution for which inequality?

Mathematics
1 answer:
Helen [10]3 years ago
8 0

Step-by-step explanation:

0 is right in the middle of all negative and all positive numbers.

0 is therefore larger than any negative number and smaller than any positive number.

and 0×n = 0, always, no matter what n is.

-0 = +0 = 0.

so, of course, only

4.1m > -16.4

is correct.

0 is not greater than 16.4.

0 is not smaller than -16.4.

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A person creates a game in which a person pays $5.00 to play. Then, they draw a single card from a standard shuffled deck of car
valkas [14]

Answer:

Step-by-step explanation:

The expected value is the probability of an event multiplied by the number of times the event happens. And if there is more than 1 event, the expected value is the sum of those.

There are 52 cards in a deck.

There are 12 face cards in a deck. (gain 10)

There are 4 ace in a deck. (gain 20)

Any other card is 36 of them. (lose 5)

The probability of face card is 12/52

The probability of ace is 4/52

The probability of any other card is 36/52

Thus the expected values is:

(12/52)(10) + (4/52)(20) + (36/52)(-5) = $0.38

3 0
3 years ago
Read 2 more answers
What is the answer for this problem 6x+3=5x
liberstina [14]
Okay so the first thing you need to do is move the all the variables to one side of the equal sign

5 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
What is 5 1/2 +2 1/7 due in one hour help please
nika2105 [10]

Answer:

7 9/14

Step-by-step explanation:

1/2=7/14

1/7=2/14

7/14+2/14=9/14

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6 0
2 years ago
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Solve for unknown: 45/15=R/9
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~~~~~~~\dfrac{45}{15} = \dfrac{R}9\\\\\\\implies \dfrac{R}9 = 3\\\\\\\implies R = 9 \times 3\\\\\\\implies R =27

8 0
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