Answer:
Inflamabilidad y características de la llama: el hidrógeno es inflamable en el aire en un amplio rango de concentraciones y arde, en ausencia de impurezas, con una llama casi invisible. Energía de ignición: el hidrógeno puede entrar en ignición con una cantidad de energía muy pequeña.
Explanation:
espero te sirva✍️
Here we have to explain and get the product of the reaction between 3-methyl-1,3-diol and chromium-tri-oxide (CrO₃)
The reaction between 3-methyl-1,3-diol with chromium-tri-oxide (CrO₃) form 3-methyl-3-hydroxybutanal.
The CrO₃ is used as a mild oxidant to the alcohol. It only produces aldehyde or ketone depending upon the position of the -OH group in a secondary or primary alcohol.
Here we can see there are two hydroxy (-OH) group in the reactant. However one of the hydroxy is at terminal carbon atom, thus primary alcohol and other in between as tertiary alcohol.
As the reagent CrO₃ does not reacts on the tertiary -OH group thus the -OH group present at 3 position will not be oxidized. Thus only the terminal hydroxy group will oxidize to form the corresponding aldehyde.
Henceforth the final product of the reaction is 3-methyl-3-hydroxybutanal as shown in the figure.
Answer:
1038.96 kPa
Explanation:
We’ll use the ideal gas law; P1V1/T1 = P2V2/T2
P1*14.8/75.5 = 101.3*16.5/70.2
P1 = (101.3 * 16.5 * 75.5) / (70.2 *14.8)
P1 = 1038.96
I think it’s science i’m not that advanced sowwy