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Anastaziya [24]
3 years ago
9

Calculate the number of moles and the mass of the solute in each of the following solutions:(a) 2.00 L of 18.5 M H2SO4, concentr

ated sulphuric acid
(b)100.0 mL of 3.8 x 10-5 MNACN, the minimum Lethal concentration of sodium cyanide in blood serum
(c)5.50 L of 13.3 M H2CO, the formaldehyde used to "fix" tissue samples.
(d)325 mL of 1.8 x 10-6 M FeSO4, the minimum concentration of iron sulphate detectable by taste in drinking water.
Chemistry
1 answer:
Vlad [161]3 years ago
5 0

Explanation:

c=\frac{n}{V}

c = Concentration of the solution

n = Moles of compound in solution

V = Volume of the solution

a) 2.00 L of 18.5 M of concentrated sulfuric acid.

n= ? c = 18.5 M, V = 2.00 L

18.5 M=\frac{n}{2.00 L}

n = 37 moles of sulfuric acid

b) 100.0 mL of 3.8\times 10^{-5} M of  sodium cyanide

n= ? ,c = 3.8\times 10^{-5} M, V = 100.0 mL = 0.1 L

3.8\times 10^{-5} M=\frac{n}{0.1 L}

n = 3.8\times 10^{-6} moles of sodium cyanide

c) 5.50 L of 13.3 M of concentrated formaldehyde.

n= ? c = 13.3 M, V = 5.50 L

13.3 M=\frac{n}{5.50 L}

n = 73.15 moles of formaldehyde.

d)325 mL of 1.8\times 10^{-6} M of  iron sulphate

n= ? ,c = 1.8\times 10^{-6} M, V = 325 mL = 0.325 L

1.8\times 10^{-6} M=\frac{n}{0.325 L}

n = 5.85\times 10^{-7} moles of iron sulfate.

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What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?
garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

M=\frac{4.4mol}{1.5L} =2.9 M

7 0
3 years ago
When heated to 150 ºC, CuSO4.5 H2O loses its water of hydration as gaseous H2O. A 2.50 g sample of the compound is placed in a s
Katyanochek1 [597]

Answer:

Water pressure 0.5 atm

Total Pressure= 2.27  atm

Explanation:

To answer this problem, one has to realize that there are two processes that increase the temperature of the sealed vessel.

First, the dry air in the sealed vessel will be heated which will cause its pressure to increase and it can be determined by the equation:

P₁ x T₂   = P₂ x T₁  ∴  P₂ =  P₁ x T₂ / T₁

For the second process, we have an amount of n moles of water which will be released when the copper sulfate is heated. In this case, to determine the value of the the water gas we will use the gas law:

   PV = nRT  ∴ P =  nRT/V

n will we calculated from the quantity of sample.

2.50 g  CuSo₄ 5H₂O x  1 mol/ 249.69 g = 0.01 mol CuSo₄ 5H₂O

the amount water of hydration is

= 0.01 mol CuSo₄ 5H₂O * 5 mol H₂O / 1 mol CuSo₄ 5H₂O

= 0.05 mo H₂O

pressure of dry air at the final temperature,

P₂ = 1 atm x 500 K/ 300 K = 1.67 atm

Pressure of water :

P (H₂O) 0.05 mol x 0.08206 Latm/kmol x 500 K/ 4 L = 0.5 atm

∴ Total Pressure =  1.67 atm

H2O Pressure = 0.5 atm

5 0
3 years ago
Two solids of identical mass, A and B, are analyzed using identical calorimeters. Each calorimeter contains the same amount of w
DIA [1.3K]

Answer:

Specific heat of solid A is greater than specific heat of solid B.

Explanation:

In the calorimeter, as the temperature is increasing, the vibrational kinetic energy will increase and this means that additional amount of energy will be needed to increase the temperature by the same value. Therefore, we can conclude that specific heat increases as temperature increases.

Now, we are told that the final temperature of solid A's calorimeter is higher than that of B.

This means from our definition earlier, Solid A will have a higher specific heat that solid B.

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