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3 years ago

Which of these pH values indicates a basic solution?

Chemistry

1 answer:

Ivahew [28]3 years ago

7 0

Answer:

The pH scale is often said to range from 0 to 14, and most solutions do fall within this range, although it's possible to get a pH below 0 or above 14. Anything below 7.0 is acidic, and anything above 7.0 is alkaline, or basic.

Explanation:

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What is the mole fraction of sodium chloride in solution that is 13. 0 y mass sodium chloride and that has a density of 1. 10 g/

lyudmila [28]

Mole fraction is the ratio of the constituent moles to the total constituents. The mole fraction of sodium chloride is 0.0443.

<h3>What is a mole fraction?</h3>

A mole fraction is the proportion of the moles of the component in a total component present.

In 100 gm of solution 13.0 5 means, there is 13.0 gm of sodium chloride present. The mass of water is calculated as,

100 - 13.0 = 87.0 gm

Moles of sodium chloride is calculated as:

$\begin{aligned} \rm moles &= \rm \dfrac{mass}{molar\; mass} \\\\&= \dfrac{13}{58}\\\\&= 0.224 \;\rm moles\end{aligned}$

Moles of water are calculated as:

$\begin{aligned} \rm moles &= \rm \dfrac{mass}{molar\; mass} \\\\&= \dfrac{87}{18}\\\\&= 4.83\;\rm moles\end{aligned}$

Now, moles fraction is calculated by dividing moles of sodium chloride by total moles as,

$\begin{aligned} \text{Mole fraction of NaCl} &= \dfrac{0.224}{0.224 + 4.83}\\\\&= 0.0443\end{aligned}$

Therefore, the mole fraction of sodium chloride is 0.0443.

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2 years ago

A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.

amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = time passed by the sample = 60.0 min

a = let initial amount of the reactant = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

$k=\frac{2.303}{60.0}\log\frac{100g}{75g}$

$k=4.79\times 10^{-3}\text{ years}^{-1}$

Now we have to calculate the half-life of the compound.

$k=\frac{0.693}{t_{1/2}}$

$4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=144.676\text{ years}\approx 145\text{ years}$

Therefore, the half-life of the compound is, 145 years.

8 0

4 years ago

Lithium seems to have dramatic effects on the nervous system, yet our bodies seemingly never evolved to use lithium endogenously

Flauer [41]

Given its small size and high polarizing power, lithium is only involved in covalent rather than ionic bonds in the body as does sodium, potassium, and calcium.

<h3>What is lithium?</h3>

Lithium is a metal and a member of group 1 in the periodic table. It is a very small ion hence it has a different chemistry from the rest of the members of the group.

Lithium is not part of any of the biomolecules because given its small size and high polarizing power, it is only involved in covalent rather than ionic bonds in the body as does sodium, potassium, and calcium.

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2 years ago

On the accompanying structural formula,<br> circle the acid functional group, only.

melisa1 [442]

The -COOH attached to the CH3 is the acid functional group.

<h3>What is a functional group?</h3>

The term functional group refers to the atom, group of atoms or bond which accounts for the chemical reactivity of a compound.

The acid functional group is known by the formula -COOH. In this case, we can see that the -COOH attached to the CH3 is the acid functional group.

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2 years ago

What is hydroxide ion concentration, [OH-], in a 1.37 x 10^-5 M solution of barium hydroxide (Ba(OH)2)?

Olegator [25]

Ba(OH)₂ is a strong base, therefore completely ionises in the solution as follows
Ba(OH)₂ --> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ gives out 2 mol of OH⁻
therefore number of OH⁻ moles are twice the amount of Ba(OH)₂ moles in the solution
hence,
[OH⁻] = 2[Ba(OH)₂]
therefore hydroxide ion concentration = 2 x 1.37 x 10⁻⁵ M
[OH⁻] = 2.74 x 10⁻⁵ M
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exponent = -5

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3 years ago