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Leviafan [203]
3 years ago
13

What is the mass of the Iron (Fe) involved in this reaction? (4pts) 1

Chemistry
1 answer:
guajiro [1.7K]3 years ago
5 0

I Would Think that the answer is 55.845 u ± 0.002 u  

Or you could just do<u> 55.85 Grams</u>

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4. Calculation of theoretical yield and percent yield You balanced this reaction earlier: Mg(s) + HCl (aq) H2 (g) + MgCl2 (aq) Y
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Mg(s) +<em> 2</em> HCl (aq) →  H₂(g) + MgCl₂

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Explanation:

Balancing the reaction:

Mg(s) + HCl (aq) →  H₂(g) + MgCl₂

There are in products two atoms of H and Cl, the balancing equation is:

Mg(s) +<em> 2</em> HCl (aq) →  H₂(g) + MgCl₂

<em>Assuming you add 10g of Mg(s) -Limiting reactant-</em>

<em />

10g of Mg are (Atomic mass: 24.305g/mol):

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