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2 years ago

What is the mass of the Iron (Fe) involved in this reaction? (4pts) 1

Chemistry

1 answer:

guajiro [1.7K]2 years ago

5 0

I Would Think that the answer is 55.845 u ± 0.002 u

Or you could just do 55.85 Grams

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A solution is made by mixing 37.g of thiophene C4H4S and 72.g of heptane C7H16. Calculate the mole fraction of thiophene in this

guajiro [1.7K]

Answer:

0.38

Explanation:

Molar mass of thiophene= 84g/mol

Mass of thiophene = 37g

Number of moles= 37/84= 0.44 moles

Molar mass of heptane= 100 g/mol

Mass of heptane = 72g

Number of moles = 72/100= 0.72 moles

Total number of moles= 0.44 + 0.72= 1.16 moles

mole fraction of thiophene = 0.44/1.16= 0.38

4 0

3 years ago

A certain mass of nitrogen gas occupies a volume of 7.56 L at a pressure of 5.08 atm. At what pressure will the volume of this s

faust18 [17]

Answer:

P₂ = 3.86 atm .

Explanation:

We assume that during this change , the temperature of the gas remains constant .

So the gas will obey Boyle's law .

P₁ V₁ = P₂V₂

5.08 x 7.56 = P₂ x 9.94

P₂ = 3.86 atm .

8 0

3 years ago

The what and what properties of a substance affect how substances in a mixture seperate

kompoz [17]

Psychical(you see the changes visible) and Chemical properties(they react and combine, you may see fizzing or bubbles).

7 0

3 years ago

An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.

____ [38]

Answer:

(a) Density of the air = 1.204 kg/m3

(b) Pressure = 93772 Pa or 0.703 mmHg

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

$\rho_{air}=\frac{P}{R*T}$

First, we change the units of P to Pa and T to deg K:

$P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K$

Then we have

$\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}$

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

$PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg$

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

$F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N$

7 0

3 years ago

Can you help me solve this problem???? How many carbon atoms are there in 2.12 molecules of propane? (C3H8)

zhenek [66]

Number of moles = 2.12 mol C3H8.
1 mol C3H8 = 6.02 × 1023 molecules C3H8.
1 molecule C3H8 = 11 atoms.
(3 carbon atoms and 8 hydrogen atoms)

3 0

3 years ago