Answer:
a) 0.06
b) 0.778
Step-by-step explanation:
Let's suppose a community of 100 families just to facilitate the calculation.
30% of the families own a dog
Dog = 30% of 100 = 30
20% of the families that own a dog also own a cat = 20% of 30 = 6
27% of all the families own a cat = 27% of 100 = 27
So, 6 families own a dog and a cat.
As 30 families own a dog, [30 - 6 =] 24 families own only dogs
As 27 families own a cat, [27 - 6 = ] 21 families own only cats
See picture attached.
a) What is the probability that a randomly selected family owns both a dog and a cat?
P(dog and cat) = dog ∩ cat/total = 6/100 = 0.06
b) What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
So, only cat/total cat
P (not dog|cat) = 21/27 = 0.778
Answer:
There is association between survival and treatment H1: there is no association between survival and treatment.
Step-by-step explanation:
Answer:
x =√25-16
x =√9
x =3
Step-by-step explanation:
I've used the Pythagoras theorem
Answer: True
The set of whole numbers is {0, 1, 2, 3, 4, 5, ...}
The set of natural numbers is {1, 2, 3, 4, 5, ...}
Both sets describe numbers that are positive and without any fractional or decimal component. The only difference is that 0 is included in the first set, but exclude from the second. If you want to include negative whole numbers as well, then you'd use the set of integers.
Label the points A,B,C
- A = (1,2)
- B = (4,5)
- C = (8,9)
Let's find the distance from A to B, aka find the length of segment AB.
We use the distance formula.
Segment AB is exactly 
units long.
Now let's find the distance from B to C
Segment BC is exactly 
units long.
Adding these segments gives
----------------------
Now if A,B,C are collinear then AB+BC should get the length of AC.
AB+BC = AC
Let's calculate the distance from A to C
AC is exactly 
units long.
Therefore, we've shown that AB+BC = AC is a true equation.
This proves that A,B,C are collinear.
For more information, check out the segment addition postulate.
