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3 years ago

Find the equation of the line that passes through A and B

Mathematics

2 answers:

beks73 [17]3 years ago

5 0

Answer:

Equation of a line is y = mx + c

where m is the slope

c is the y intercept

To find the equation that passes through the points we must first find the slope of the points

A(4,7) and B (2,3)

Slope = 3 - 7 / 2 - 4 = -4/-2 = 2

Equation of the line that passes through points A(4,7) and B (2,3) is

Using point B ( 2 ,3)

y - 3 = 2( x - 2)

y = 2x - 4 + 3

y = 2x - 1

Hope this helps you

Alex777 [14]3 years ago

4 0

Answer:

First we need to find the slope. This is (7 - 3) / (4 - 2) = 2. Since we know the slope, we can use point-slope form. I'm using the point (2, 3).

y - 3 = 2(x - 2)

y - 3 = 2x - 4

y = 2x - 1

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Hii Please Answer ASAP and only if you know the answer! :P I will give brainliest to right answer!! :)

olga nikolaevna [1]

Answer:

Step-by-step explanation:

Here so u can give that person brainliest

5 0

3 years ago

The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

A line that includes the points (7,u) and (6,6) has a slope of -8. What is the value of u?

Zielflug [23.3K]

Answer:

(6-u)/(6-7)= (6-u)/-1= 8

6 - u = -8

-u = -14

u = 14

8 0

4 years ago

Read 2 more answers

6.) ? Need help with the steps

Law Incorporation [45]

Well you equal out the two angles to each other and solve for x. then you just plug the the number you got for x back into the equations to get your answers

3 0

3 years ago

Justin has a crate that is 8 feet long 2 feet wide and 3 feet tall decide weather each of the crate sizes described below has th

Nuetrik [128]

Complete question is;

Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall. Decide whether each of the crate sizes described below has the same volume as Justin’s crate.

a. 9 feet long, 1 foot wide, 4 feet tall

b. 8 feet long, 2 feet wide, 2 feet tall

c. 4 feet long, 4 feet wide, 3 feet tall

d. 8 feet long, 3 feet wide, 3 feet tall

e. 6 feet long, 2 feet wide, 4 feet tall Answer:

Options C & E have the same volume as Justin's crate.

Step-by-step explanation:

We are told Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall.

Thus, original volume is;

V_o = 8 × 2 × 3 = 48 ft³

A) For a dimension of 9 feet long, 1 foot wide, 4 feet tall , volume is;

V_a = 9 × 1 × 4 = 36 ft³

B) For a dimension of 8 feet long, 2 feet wide, 2 feet tall, volume is;

V_b = 8 × 2 × 2 = 32 ft³

C) For a dimension of 4 feet long, 4 feet wide, 3 feet tall, volume is;

V_c = 4 × 4 × 3 = 48 ft³

D) For a dimension of 8 feet long, 3 feet wide, 3 feet tall, volume is;

V_d = 8 × 3 × 3 = 72 ft³

E) For a dimension of 6 feet long, 2 feet wide, 4 feet tall, volume is;

V_e = 6 × 2 × 4 = 48 ft³

Looking at all the options, the only ones that given a volume equal to Justin's original volume are options C & E.

4 0

3 years ago