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2 years ago

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If x varies inversely as y and x=2.5 when y = 40 , find y when x = 2

1 answer:

Illusion [34]2 years ago

6 0

Answer:

2.5/40=2/y

2.5y=40x2

2.5y=80

y=80/2.5

y=32

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The average number of traffic tickets issued in a city on any given day

Anton [14]

Answer:

The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by

$T(x) = -6x^2 + 84x + 37$

Where x represents the number of days after Sunday

T(x) represents the number of traffic tickets issued.

Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute x= 0

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37$

On Sunday 37 tickets were issued

Substitute x= 1

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(1)^2 + 84(1) + 37\\T(x)=115$

On Monday 115 tickets were issued

Substitute x= 2

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181$

On Tuesday 181 tickets were issued

Substitute x= 3

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(3)^2 + 84(3) + 37\\T(x)=235$

On Wednesday 235 tickets were issued

Substitute x= 4

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(4)^2 + 84(4) + 37\\T(x)=277$

On Thursday 277 tickets were issued

Substitute x= 5

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307$

On Friday 307 tickets were issued

Substitute x= 6

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325$

On Saturday 325 tickets were issued

Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

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3 years ago

Directions-Graph the following slope intercept equation

FromTheMoon [43]

0,-2

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7 0

2 years ago

The moon has a surface area of approximately 14,650,000 m^2. Estimate its radius to the nearest mile

Elza [17]

$\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=14650000 \end{cases}\implies 14650000=4\pi r^2 \\\\\\ \cfrac{14650000}{4\pi }=r^2\implies \cfrac{3662500}{\pi }=r^2\implies \sqrt{\cfrac{3662500}{\pi }}=r\implies 1079.73\approx r$

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3 years ago

Solve 5x+7 > 17.<br> {x1x<2}<br> O {XIX> 2}<br> O {xIx>-2}<br> O {x1x < -2}

fgiga [73]

Answer:

The answer is $x > 2$

Step-by-step explanation:

to solve this inequality:

$5x+7 > 17$

Put "-7" on both sides

$5x+10$

divide by 5 on both sides

your answer should be 2.

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1 year ago

F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.

Rom4ik [11]

Answer:

$15.~f(g(2))=\Large\boxed{11}\\$

$16.~g(f(2.5))=\Large\boxed{16}$

$17.~g(f(-5))=\Large\boxed{1}$

$18.~f(g(-5))=\Large\boxed{-3}$

Step-by-step explanation:

<h3>Given information</h3>

$f(x)=x+4$

$g(x)=2x+3$

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

$g(2)=2(2)+3$

$g(2)=4+3$

$g(2)=7$

<u>Substitute the values of the first function into the second</u>

$f(g(2))=f(7)$

$f(7)=(7)+4$

$f(7)=\Large\boxed{11}$

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

$f(2.5)=(2.5)+4$

$f(2.5)=6.5$

<u />

<u>Substitute the values of the first function into the second</u>

$g(f(2.5))=g(6.5)$

$g(6.5)=2(6.5)+3$

$g(6.5)=13+3$

$g(6.5)=\Large\boxed{16}$

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

$f(-5)=(-5)+4$

$f(-5)=-1$

<u>Substitute the values of the first function into the second</u>

$g(f(-5))=g(-1)$

$g(-1)=2(-1)+3$

$g(-1)=-2+3$

$g(-1)=\Large\boxed{1}$

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

$g(-5)=2(-5)+3$

$g(-5)=-10+3$

$g(-5)=-7$

<u>Substitute the values of the first function into the second</u>

$f(g(-5))=f(-7)$

$f(-7)=(-7)+4$

$f(-7)=\Large\boxed{-3}$

Hope this helps!! :)

Please let me know if you have any questions

7 0

1 year ago