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Archy [21]
3 years ago
12

Verify as an identity: cos(90°+x) = -sinx I'm not sure how to go about this question

Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0
Cos( a + b ) = cosa×cosb - sina×sinb ; 
a = 90 and b = x ;
But, cos90 = 0 and sin90 = 1;
cos( 90 + x ) = 0 × cosx - 1 × sinx = - sinx ; 
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??????????????????????
natita [175]

Answer:

Figure out what x is for both equations, then you can tell if the equations are the same

Step-by-step explanation:

1. 4x+1=9

x = 2

4 x 2= 8

2x+1=5

x = 2

2 x 2 = 4

4 does not = 9 so no.

4 0
3 years ago
the 90 members of a service Club had the opportunity to vote for a club officers on Tuesday or Wednesday 3/5 of the members vote
oee [108]
For this problem, it is really important to find who voted on Tuesday first.
90×(3/5)= 54 
54 people voted on Tuesday. Since the people who voted on Wednesday was 1/4 of the members who did not vote on Tuesday.
90-54=36×(1/4)=9
9 people voted on Wednesday. Now add Tuesday and Wednesday together to find the ones that didn't vote.
54+9=63;90-63=27
27 people did not vote at all.
6 0
3 years ago
Read 2 more answers
An electrician charges a rate of $60 per hour plus a fee of $35 per job. Which expression represents the electrician's hourly ra
miskamm [114]

The hourly rate is 60, so multiply 60 by the number of hours (h) and add the fee:

Answer: 60h + 35

5 0
2 years ago
Find the total of the figure below. PLEASEEE HELPPPPPPPP!
KATRIN_1 [288]
The answer is 134 ft^2



the area of the smaller rectangle:
5 \times 6 = 30



the area of the other rectangle:
8 \times 13 = 104




the area of the whole shape:
104 +30 = 134



good luck
3 0
3 years ago
dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq
dem82 [27]
Let the side of the garden alone (without walkway) be x.  
Then the area of the garden alone is x^2.  
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and 
 2) four squares, each of area 2^2 square feet.


The total walkway area is thus x^2 + 4(2^2) + 4(x*2).  

We want to find the dimensions of the garden.  To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18.  We must discard x=-18, since the side length can't be negative.  We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.


4 0
3 years ago
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