Considering the values of the digits in the number, we have that digit 2 has a value that is 1/10 the value of the 7 in the ten thousand place.
<h3>What are the values of the digits in the number 1,377,207?</h3>
We start counting the values from the final number, from 1 and multiplying by 10, hence:
- Digit 7 has a value of 1.
- Digit 0 has a value of 10.
- Digit 2 has a value of 100.
- Digit 7 has a value of 1,000.
- Digit 7 has a value of 10,000. -> Ten thousand place.
- Digit 3 has a value of 100,000.
- Digit 2 has a value of 1,000,000.
One tenth of the ten thousand place is a value of 100, hence digit 2 has a value that is 1/10 the value of the 7 in the ten thousand place.
More can be learned about the values of the digits in a number at brainly.com/question/2041524
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Answer:
360 sq. units
Step-by-step explanation:
area of DOIT = (20+20) × (3+6)
= 40×9 = 360 sq. units
1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5
2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18
Average= f(2)−f(0)/2−0
=62.5−250/ 2-0
<span>= −93.75</span>