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velikii [3]
3 years ago
12

A line passes through the points (0, 2) and (2, 10). What is its equation in slope-intercept form?

Mathematics
2 answers:
levacccp [35]3 years ago
6 0

Answer:

  • y = 4x + 2

Step-by-step explanation:

<u>The slope-intercept form:</u>

  • y = mx + b, where m is the slope, b is the y-intercept

<u>Find the slope using given points:</u>

  • m = (10 - 2)/(2 - 0) = 8 / 2 = 4

<u>The y-intercept is given with point (0, 2):</u>

  • b = 2

<u>The line is:</u>

  • y = 4x + 2
Alex Ar [27]3 years ago
6 0
  • (0,2)
  • (2,10)

\\ \sf{:}\Rrightarrow m=\dfrac{10-2}{2-0}=\dfrac{8}{2}=4

Put in slope intercept form

\\ \sf{:}\Rrightarrow y=mx+b

\\ \sf{:}\Rrightarrow 2=4(0)+b

\\ \sf{:}\Rrightarrow 2=b

Equation of the line

\\ \sf{:}\Rrightarrow y=4x+2

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\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1.25)}=\stackrel{m}{-\cfrac{1}{4}}(x-\stackrel{x_1}{(-1)}) \\\\\\ y+1.25=-\cfrac{1}{4}(x+1)\implies y+\cfrac{5}{4}=-\cfrac{1}{4}x-\cfrac{1}{4} \\\\\\ y=-\cfrac{1}{4}x-\cfrac{1}{4}-\cfrac{5}{4}\implies y=-\cfrac{1}{4}x-\cfrac{6}{4}\implies y=-\cfrac{1}{4}x-\cfrac{3}{2}

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