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marshall27 [118]
3 years ago
11

Able, Ben and Cal each played a game able’s score was six times ben’s score, Cale score was a hird time of Able’s score write do

wn the ratio of abels score to bens score to cals score , write ratio in simplest form?
Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Answer:

6:1:2

Step-by-step explanation:

Let a = Able's score, b = Ben's score, and c = Cal's score.

Since

Able's score was 6 times Ben's score, that means a = 6b.

Cal's score was a third of Able's score, so that means c = a/3. And since a = 6b, that means c = 6b / 3 = 2b.

Thus, the ratio of Able's score to Ben's score to Cal's score, a:b:c, is 6:1:2, because c is twice as much as b and a is 6 times as much as b.

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The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.
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Answer:

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Step-by-step explanation:

Please find the attachment.  

We have been given that area of triangle ABC is 3√2 square inches.

\text{Area}=\frac{1}{2}\text{Base}\times \text{height}

We know that area of triangle an be found using trigonometry as:

\text{Area}=\frac{1}{2}\times c\times h

\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)

3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)

3\sqrt{2}=9\cdot \text{sin}(A)

9\cdot \text{sin}(A)=3\sqrt{2}

\text{sin}(A)=\frac{3\sqrt{2}}{9}

\text{sin}(A)=\frac{\sqrt{2}}{3}

Now, we will use inverse sine to find the value of angle A as:

A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})

A=28.1255057^{\circ}

A\approx 28^{\circ}

Therefore, the measure of angle A is approximately 28 degrees.

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