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Zielflug [23.3K]

3 years ago

5

How to find volume of a drawing of a piece of cake?

1 answer:

Ipatiy [6.2K]3 years ago

8 0

Just find the volume of a triangular prism.

volume=1/2*length*width*height.

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5p= 112.50. The 5 members of the Wyler family paid 112.50 for admission to a water park. What was the price ,p, of each ticket

Ivahew [28]

The price for each ticket is 22.41

5 0

3 years ago

Jane multiplies her number by three and subtracts 2.

katrin [286]

Answer:

Let the number they chose be 'x'.

Result of Jane = $3x -2$

Result of Elliot = $2x+3$

Given that,

The product of their result = 110

$or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}$

3 0

3 years ago

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

3 years ago

The quadrilateral shown is a rhombus. What is angle 4?<br> A; 28<br> B; 32<br> C; 58<br> D; 90

Goryan [66]

I believe the answer would be A 32.

This is because 3 is congruent to 4.

6 0

2 years ago

5,400 inches to miles

Anit [1.1K]

1inch= 0,8(3) feet

5,400*0,8333 : 5280= 4,4999 :5280=0, 085 miles

4 0

3 years ago

Read 2 more answers