Answer:
When the price of a ticket = $0 or $40, there will be no revenue.
The revenue will be $500 if each ticket cost $37.3 or $2.68
Step-by-step explanation:
Let R(p) = p(200-5p)
when R(p) = 0
p(200-5p) = 0
p = 0 or 200-5p = 0
When the price of a ticket = $0 or $40, there will be no revenue.
when R(p) = 500
200p - 5p² = 500
5p² - 200p + 500 = 0
p = $37.3 or $2.68 (3 sig. fig.)
The required prices are $37.3 and $2.68
C=-3. (2c)^3
(2(-3))^3
(2-3)^3
(-1)^3
-1*-1*-1=
-1
You can have a maximum of 3 groups. This is due to the fact that you only have 3 sopranos to equally divide between groups. Over 3 you would have a group lacking a soprano so 3 is the greatest you can make it.
In this problem, we need to plug in the given x values for

and find a and b.
When we plug in 1, we get:

Simplify:



We got our first statement about the values of the variables. If we find one more we can find those 2 variables.
We have another given root: 4.
Plug it in:




Now we have our second one. We can combine them:

I use elimination method which is easier here.
Multiply the top equation by -1:

Add them up:

Simplify:

Now we have a, we can plug in one of those equations to find b:



So, the answers are

and

.
Answer: 5/8
Step-by-step explanation:
3/8 + 5/8
Thanks for the free points