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UNO [17]
3 years ago
7

Please help me out !!

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0
<h3>Solution:</h3>

\huge \pink {\tt {{128}^{ \frac{3}{7} }  =  \sqrt[7]{ {128}^{3} }  =  {2}^{3}  }}

\huge \pink {\tt {= 8}}

<h2>Answer:</h2>

\huge \purple {\tt {8 \: is \: the \: answer}}

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In March it rained 4 inches less than April than in march. How much did it rain in April?
Elenna [48]

Step-by-step explanation:

4 inches less  means

April = a

March = a - 4

Hope this helps :)

4 0
3 years ago
Need answers for Question 8 and 9
Advocard [28]

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6 0
3 years ago
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I don’t get this Please help
ValentinkaMS [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Calculate the value of the sample variance. Round your answer to one decimal place. 9_5,9_5,2,9_5
Ugo [173]

Answer:

s^2 = 0.01

Step-by-step explanation:

Given

Values: 9/5, 9/5, 2, 9/5

Required

Calculate the sample variance

Sample variance is calculated using:

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1}

First, we calculate the mean

\overline x = \frac{\sum x}{n}

\overline x = \frac{9/5 + 9/5 + 2 + 9/5}{4}

\overline x = \frac{7.4}{4}

\overline x = 1.85

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1} becomes

s^2 = \frac{(9/5 - 1.85)^2+(9/5 - 1.85)^2+(2 - 1.85)^2+(9/5 - 1.85)^2}{4 - 1}

s^2 = \frac{(-0.05)^2+(-0.05)^2+(0.15)^2+(-0.05)^2}{4 - 1}

s^2 = \frac{0.0025+0.0025+0.0225+0.0025}{3}

s^2 = \frac{0.03}{3}

s^2 = 0.01

<em>Hence, the variance is 0.01</em>

5 0
3 years ago
Need help i have been stuck on this problem
liberstina [14]
The second one is correct
4 0
3 years ago
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