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Reptile [31]
3 years ago
13

Four students are running for class president: liz, sam, sue, and tom. the probabilities of sam, sue, and tom winning are 7⁄25 ,

3⁄10 and 21⁄100 , respectively. what is the probability of liz winning?
Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0
First, we need to convert all the fractions to have the same denominator. 10 and 25 are both multiples of 100, so 100 would be appropriate. 

Sam has a 7/25 chance. Because we want ?/100, something needs to change. To get from 25 to 100, you need to times 25 by 4, right? So, do the same with the 7.
7 x 4 = 28. Therefore Sam has a 28/100 chance.

Sue has 3/10. Using the same method, we can see that 3 needs to be multiplied by 10 (because 10 times 10 = 100). So Sue has a 30/100 chance.

Tom is already in the fraction we like, so just keep this as 21/100. 

Now, add 28/100, 30/100 and 21/100 to get 79/100. 

Because won of them will get the role of class president, we know that the probability adds to 1. To get a full probability (100/100, or 1), what needs to be added to 79/100? 

Another way of going about this is 100/100-79/100. The answer is 21/100

The probability of Liz winning is 21/100. 

Let me know if this is still unclear, I would be more than happy to explain in more detail if necessary :) 
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lions [1.4K]

Answer:

perimetro = \dfrac{(3 + \sqrt{3})m}{2}

Step-by-step explanation:

triángulo 30°-60°-90°

1~:~\sqrt{3}~:~2

1m~:~m\sqrt{3}~:~2m

\dfrac{m}{2}~:~\dfrac{m\sqrt{3}}{2}~:~m

perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + m

perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + \dfrac{2m}{2}

perimetro = \dfrac{m + m\sqrt{3} + 2m}{2}

perimetro = \dfrac{3m + m\sqrt{3}}{2}

perimetro = \dfrac{(3 + \sqrt{3})m}{2}

7 0
3 years ago
1/3 divided by 4 someone help!!
kozerog [31]

Answer:

1/12

Step-by-step explanation:

1/3 x1/4=1/12

6 0
3 years ago
Read 2 more answers
Slope and y-intercept form from a table
dsp73

Answer:

The y-intercept is 3

Gradient: 4

11-3= 8

2-0= 2

8/2= 4

Hope this helped!

 

4 0
2 years ago
Using the digits 1 to 9 at most one time each, fill in the boxes to find the largest (or smallest) possible values for x.
Mice21 [21]

Answer:

smallest: 8x -3 = 4; 1y +9 = 2. total = -49/8

 largest: 1x -9 = 8; 2y +3 = 7. total = 19

Step-by-step explanation:

If we use variables to represent the box contents, we can write ...

ax -b = c

dy +e = f

Then the values of x and y are ...

 x = (c +b)/a

 y = (f -e)/d

For positive integer values of the variables, x will always be positive, and y may or may not be negative.

Smallest sum

For the sum to be the smallest, we must have x be as small as possible and the ratio (f-e)/d be as negative as possible.

x will be small for large 'a' and for (c+b) small. For y to be as negative as possible, we want 'd' and 'f' small and 'e' large. Best results are obtained for

8x -3 = 4   ⇒   x = 7/8

1y +9 = 2   ⇒   y = -7

For these coefficients, the sum is -6 1/8 = -49/8.

(note that the values of 'b' and 'c' can be swapped with no net effect)

Largest sum

For the sum to be the largest, we must have x as large as possible: (b+c) large and 'a' small. At the same time we must have y be positive and as large as possible: (f-e) positive and large, 'd' small. Best results are obtained for

1x -9 = 8  ⇒   x = 17

2y +3 = 7   ⇒   y = 2

For these coefficients, the sum is 19. Again, 'b' and 'c' can be swapped with no effect.

_____

Additional comment

These extreme values are verified by examination of the 60,480 possible permutations of the coefficients.

8 0
3 years ago
Which of the following expressions is equal to 3x^2 + 27
Kisachek [45]
Factor: 
3x^2 + 27
= 3(x^2  + 9)
Answer is 3(x^2 + 9), when factored.


A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2



B) (3x - 9i)(x + 3i)
= (3x +  - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2


C) (3x - 6i)(x + 21i)
= (3x +  - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
=  - 126i^2 + 57ix + 3x^2






D) (3x - 9i)(x - 3i)
=  (3x +   - 9)(x +  - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x









Hope that helps!!!

8 0
3 years ago
Read 2 more answers
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