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3 years ago

15

HELP I’ll give you brainliest This is timed I have 5 minutes

1 answer:

DiKsa [7]3 years ago

4 0

Pretty sure it’s y=(x-5)^2+7

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Can yall help me with

Vaselesa [24]

Answer:

B

Step-by-step explanation:

x(2y - 3) ← multiply each term in the parenthesis by x

= 2xy - 3x

3 0

8 months ago

Pls help me with this

kvasek [131]

Answer:

1st one is positive

2nd one is negative

3rd one is negative

4th one is positive

Step-by-step explanation:

7 0

2 years ago

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

3 years ago

Add a explanation with your answer

Alenkasestr [34]

I hope this helps !!

8 0

2 years ago

Joshua sponsored a fundraiser that 708 people attended. He raised $8,640. He charged $15 for balcony seats and $10 for ground se

lozanna [386]

312 people bought balcony seats and 396 people bought ground seats.

5 0

2 years ago