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USPshnik [31]
4 years ago
7

​the unified modeling language (uml) represents an object as a _____ with the object name at the top, followed by the object's a

ttributes and methods.
Computers and Technology
1 answer:
Ghella [55]4 years ago
6 0

An object in UML is drawn as a rectangle, typically creating two columns. The top column will contain the name and bottom column will contain attributes of the object.

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Transmits data as pulses of light through tiny tubes of glass Uses standard telephone lines to create a high-speed connection Co
defon

Answer:

The answer is "True".

Explanation:

To transfer data, the fiber optic wire used a high-speed data transmission medium, which includes a small glass or plastic polymers, that carry the light beam to transmit data through swift light flashes through the cable.

  • It enables the transmission of data more quickly over larger distances.
  • In this cable, the traditional cable use to provide web data transfer to cable TV, that why the given statement is true.
4 0
3 years ago
Use System.DateTime along with System.Console to implement a simple C# program that does the following:_______.
Andre45 [30]

Answer:

5

Explanation:

I did it to and it was right

3 0
3 years ago
2. "The only requirement for a person to use a computer is that you should be able to read and
Lena [83]

Answer:

False.

Explanation:

Most computers have options that allow you to change the language if needed.

6 0
3 years ago
A computing company is running a set of processes every day. Each process has its own start time and finish time, during which i
Helga [31]

Answer:

Above all else, let us show that this issue has the greedy choice property.

This implies that worldwide ideal arrangement can be gotten by choosing local ideal arrangements. Presently notice the following:

The global optimal solution of the issue requests us to track down the minimum number of times process_check module should be run.

It is likewise referenced that during each running interaction, process_check module should be called atleast once. Along these lines, the minimum possible number of process_check calls happens when process_check is made close to the quantity of the processes that are run.

Along these lines, we see that the global optimal solution is shaped by choosing optimal answer for the nearby advances.

Along these lines, the issue shows greedy choice property. Thus, we can utilize a greedy algorithm for this issue.

The greedy step in this calculation is to postpone the process_check as far as might be feasible. Thus, it should be run towards the finish of each interaction. So the following algorithm can be utilized:

Sort the cycles by utilizing the completion times.

Towards the finish of the 1st process in the arranged list, run the process_check module. Right now any process that is now running is removed the arranged rundown. The main interaction is additionally removed from the sorted list.

Now repeat stage 2, till all processes are finished.

In the above mentioned algorithm, the costliest advance is the step of sorting. By utilizing the optimal sorting algorithm, for example, merge sort, we can achieve it in O(n log n) asymptotic time.

Along these lines, this greedy algorithm additionally takes O(n log n) asymptotic time complexity.

5 0
3 years ago
Write a method that prints on the screen a message stating whether 2 circles touch each other, do not touch each other or inters
beks73 [17]

Answer:

The method is as follows:

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

    double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

    if(d == r1 + r2){

        System.out.print("The circles touch each other");     }

    else if(d > r1 + r2){

        System.out.print("The circles do not touch each other");     }

    else{

        System.out.print("The circles intersect");     }

}

Explanation:

This defines the method

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

This calculate the distance

    double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

If the distance equals the sum of both radii, then the circles touch one another

<em>     if(d == r1 + r2){</em>

<em>         System.out.print("The circles touch each other");     }</em>

If the distance is greater than the sum of both radii, then the circles do not touch one another

<em>    else if(d > r1 + r2){</em>

<em>         System.out.print("The circles do not touch each other");     }</em>

If the distance is less than the sum of both radii, then the circles intersect

<em>    else{</em>

<em>         System.out.print("The circles intersect");     }</em>

}

6 0
3 years ago
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