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SIZIF [17.4K]
3 years ago
7

Write the line that declares a two-dimensional array of strings named chessboard. that is, how would i declare a two-dimension a

rray of strings that is called chessboard? you would declare a string array by
Computers and Technology
1 answer:
matrenka [14]3 years ago
3 0

Answer:

String chessboard[][]=new String[6][6];

Explanation:

This is the declaration of a string 2-D array in java.

String is the data type of the variable.

chessboard is the name of the variable.

6 is the size of the 2-D array.

new is the keyword for allocating  space to array.

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The type of software-generated problems that can indicate that a software bug is causing a memory error are page fault, exception error and general-protection fault. Registry errors show that there are parts of the registry that were written to the faulty parts of the RAM. An erroneous memory count would happen when there is incompatibility in the installation.
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3 years ago
From the television industry's point of view, which of the following would be the most desirable viewer?
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A 50-year-old African American man
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3 years ago
1. How many bits would you need to address a 2M × 32 memory if:
Dominik [7]

Answer:

  1. a) 23       b) 21
  2. a) 43        b) 42
  3. a) 0          b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8;  L = ( 2M * 32 ) / 8 =  2M * 4

hence number of bits =  log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 ,  item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0
3 years ago
Which of these is an example of gathering secondary data?
Soloha48 [4]

Answer:

searching for a chart

Explanation:

:)

7 0
3 years ago
Susan is working with an IT company. She has been asked to make sure that all of the functions in the company are in place and p
MrMuchimi

According to Henri Fayol, it can be said that there are five functions of management: planning, organizing, staffing, directing, and controlling. From the description in the question, it seems that Susan should employ the controlling management function – which is defined as ensuring that all the ongoing process are proceeding as planned.

It is clear that this definition is precisely what Susan needs to do to fulfill the request that she was given.

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