An animal park has lions, tigers and zebras. 17% of the animals are zebras. What percentage are tigers? Show me your work!
1 answer:
Answer:
53% are tigers
Step-by-step explanation:
If you were referring to the question:
<u><em>An animal park has lions, tigers and zebras. 17% of the animals are lions and 3/10 of the animals are zebras. What percentage are tigers? Show me your work! </em></u>
We can then solve it by considering what is 3/10 in percent form.
When you think of percent, just remember that it is a portion for every 100. So think of a fraction that is proportional to 3/10 that is a fraction of 100:
So 3/10 = 30/100 which in percentage form is 30%.
Now if:
17% = lions
30% = zebras
We can get the percentage by looking for how many out of 100% is left.
100% - (17% + 30%)
100% - 47%
53%
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Answer:
There is not enough evidence to support the claim that the liquid diet yields a higher mean weight loss than the powder diet (P-value = 0.15).
Step-by-step explanation:
This is a hypothesis test for the difference between populations means.
The claim is that the liquid diet yields a higher mean weight loss than the powder diet.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample 1 (powder diet group), of size n1=49 has a mean of 42 and a standard deviation of 12.
The sample 2 (liquid diet group), of size n2=36 has a mean of 45 and a standard deviation of 14.
The difference between sample means is Md=-3.
The estimated standard error of the difference between means is computed using the formula:
Then, we can calculate the t-statistic as:
The degrees of freedom for this test are:
This test is a left-tailed test, with 83 degrees of freedom and t=-1.04, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.15) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the liquid diet yields a higher mean weight loss than the powder diet.