To determine the probability that exactly two of the five marbles are blue, we will use the rule of multiplication.
Let event A = the event that the first marble drawn is blue; and let B = the event that the second marble drawn is blue.
To start, it is given that there are 50 marbles, 20 of them are blue. Therefore, P(A) = 20/50
After the first selection, there are 49 marbles left, 19 of them are blue. Therefore, P(A|B) = 19/49
Based on the rule of multiplication:P(A ∩ B) = P(A)*P(A|B)P(A ∩ B) = (20/50) (19/49)P(A ∩ B) = 380/2450P(A ∩ B) = 38/245 or 15.51%
The probability that there will be two blue marbles among the five drawn marbles is 38/245 or 15.51%
We got the 15.51% by dividing 38 by 245. The quotient will be 0.1551. We then multiplied it by 100% resulting to 15.51%
Answer:
0.92
Step-by-step explanation:
always equals 1.0
1.0 - 0.08 = 0.92
Answer:
I believe it is 252 correct me if I'm wrong
Answer:
74 units squared
Step-by-step explanation:
we know that the area of a square or rectangle is A = L × w
so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.
so I'll start with the middle square its length is 8 and width is 8 too.
A = 8 × 8
A = 64
now we'll move on to the other small ones to the side.
the one on the right side it's length is 2 and width is 2.
A = 2 × 2
A = 4
and then the last one on the left, Length is 3, width is 2.
A = 2 × 3
A = 6
now we'll add up all of the areas to get the total area.
Total = 64 + 4 + 6
Total = 74 units squared
Answer:
Check it below, please
Step-by-step explanation:
Hi there!
Let's prove segment AB is perpendicular to CD. Attention to the fact that a two column proof has to be concise. So all the comments can't be exhaustive, but as short as possible.
Let's recap: An isosceles triangle is one triangle with at least 2 congruent angles.
Statement Reason
Given
Isosceles Triangle the altitude, the bisector coincide.
Bisector equally divide a line segment into two congruent
Right angles, perpendicular lines.
Perpendicular Line segment
