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tester [92]
3 years ago
9

A warranty identification number for a certain product consists of a letter of the alphabet followed by four-digit number. How m

any possible identification numbers are there if the first digit of the four-digit number must be nonzero?,
Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0
<span>A warranty identification number has the format: A0000 There are 26 letters in the alphabet. If the identification number has the first digit being 0 then for each letter the number can only go up to A0999. Including A0000, this means there is 1000 combinations per letter. So there is 26,000 possible identification numbers.</span>
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For the functions f(x) = x^2+ 8x + 2 and g(x) = -5+9, find (f•g)(x)and (f.g)(-1).
Ne4ueva [31]

Answer:  (f·g)(x) = -5x³ - 31x² + 62x + 18

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(fog)(x) = 25x² - 130x + 155

(fog)(-1) = 310

<u>Step-by-step explanation:</u>

f(x) = x² + 8x + 2          g(x) = -5x + 9

(f·g)(x) = (x² + 8x + 2)(-5x + 9)

          = -5x³ + 9x²

                    - 40x² + 72x

            <u>                    - 10x + 18</u>

          = -5x³ - 31x² + 62x + 18

(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18

         =  -5(-1)  - 31(1)    - 62      + 18

         =    5     -   31      - 62      + 18

         =  -70

****************************************************************************************

(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2

           = 25x² - 90x + 81

                       - 40x + 72

              <u>                   +   2</u>

           = 25x² - 130x + 155

(fog)(-1) = 25(-1)² - 130(-1) + 155

            =   25    +  130    + 155

            = 310

<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>

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Answer:

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Step-by-step explanation:

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2 years ago
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Arturiano [62]
35.

2*2= 4*2=8

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27+8=35

So the answer is 35. Hope this helps
3 0
2 years ago
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meriva

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Answer:

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