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Alex73 [517]
3 years ago
8

Which triangles can have two sides of the same lenghth

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

An isosceles triangle is a triangle with 2 congruent sides. The congruent sides are called legs and the third side is called the base. So if 2 sides of a triangle have the same length, then we say that the triangle is isosceles.

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A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
3 years ago
Wouldnt it be 15??? I would guess so. Katie keeps deleting this but Im not sure why. Sorry katie but I really need help
Anna007 [38]

Answer:

25 in; C

Step-by-step explanation:

Hey!

There probably is a reason she is deleting. You could contact her or ask some help elsewhere.

Anyway! I'm trying to get this in fast. (Remember the Pythagorean Theorem?) That will be very useful here since it is a right triangle.

<u>L² + L² = H² (or H² - L² = L²):</u>

In that case, we'll use the second one because our Hypotenuse is given.

We can substitute each value of the numbers:

65² - 60² = L²

Evaluating:

4225 - 3600 = 625

√625 = 25 inches

Thusly, the third side would be \boxed{25{\text{\:inches\:or\:C.}}}

<em>Also note we could have simplified into a Pythagorean Triple. This method is a simpler more basic method for learning the concept.</em>

Hope this helps!

3 0
3 years ago
Read 2 more answers
Lily’s sister has a bag of skittles containing 3 yellow skittles, 4 red skittles, 5 green skittles, and 3 orange skittles. What
lisov135 [29]

Answer:

Read a bit so you can understand which one you want.

<u>Percentage</u>

15 skittles, 3 of the 15 are orange.

3 over 15, or 0.2 as a percentage.

So there is a 0.8% chance that he will NOT pick an orange skittle.

<u>Fraction</u>

15 skittles, 3 over 15.

3 over 15 can be 1 over 5.

So there is a 4 over 5 chance that he WONT grab an orange skittle, pretty good odds.

6 0
3 years ago
Use the model to solve for x.<br> Please help me I will give out extra points and the brain thing.
Ganezh [65]

Answer:

x = 7/3

Step-by-step explanation:

3x - 2 =5

Add 2 to each side

3x-2+2 = 5+2

3x = 7

Divide by 3

3x/3 = 7/3

x = 7/3

8 0
3 years ago
Read 2 more answers
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
6 0
3 years ago
Read 2 more answers
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