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Alex73 [517]
3 years ago
8

Which triangles can have two sides of the same lenghth

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

An isosceles triangle is a triangle with 2 congruent sides. The congruent sides are called legs and the third side is called the base. So if 2 sides of a triangle have the same length, then we say that the triangle is isosceles.

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A spherical balloon has a circumference of 25 cm.
ArbitrLikvidat [17]

Answer:

See below ↓↓

Step-by-step explanation:

<u>Finding the radius</u>

  • C = 2πr
  • 25 = 2 x 3.14 x r
  • r = 25 / 6.28
  • r = 3.98 cm ≅ 4 cm

<u />

<u>Surface Area</u>

  • 4πr²
  • 4 x 3.14 x 4 x 4
  • 3.14 x 64
  • 200.96
  • <u>201 cm²</u>

<u></u>

<u>Volume</u>

  • 4/3πr³ = 4πr² x r/3
  • 201 x 4/3
  • 67 x 4
  • <u>268 cm³</u>
4 0
2 years ago
How would i approximate each irrational square root number to the nearest 0.05? 34, 82, 45, 104, -71, and -19
Digiron [165]

Using a calculator or a pencil, find each square root, including
three (3) decimal places.  A negative number has no real square
roots, so skip '-71' and '-19'.

For each square root . . .

-- If the digits in the 2nd and 3rd decimal place are 00 through 24, then
make the 2nd decimal place a '0' and discard the rest.

-- If the digits in the 2nd and 3rd decimal place are 25 through 74, then
make the 2nd decimal place a '5' and discard the rest.

-- If the digits in the 2nd and 3rd decimal place are 75 through 99, then
increase the 1st decimal place by 1, make the 2nd decimal place a '0',
and discard the rest.
4 0
3 years ago
the weight of a nickel is 80% of the weight of a quarter.if a nickel weighs 5grams how much does a quarter weigh?
Rasek [7]
Just divide 100% by 80% and multiply that answer by 5. I'm pretty sure that's how you do it.
8 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
Look at each equation and possible solution. Is the solution correct? Select Yes or No for each equation.
oksano4ka [1.4K]

Answer:

yes

Step-by-step explanation:

7 0
3 years ago
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