Answer: did you ever get the answer? I have this same question on a test rn
Step-by-step explanation:
Answer:
a). Area = 54 square units
b). Perimeter = 33.7 units
Step-by-step explanation:
Vertices of the triangle ABC are A(-4, -2), B(1, 7) and C(8, -2).
(a). Area of the triangle ABC =
(Absolute value)
By substituting the values from the given vertices,
Area = ![\frac{1}{2}[(-4)(7+2)+(1)(-2+2)+8(-2-7)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28-4%29%287%2B2%29%2B%281%29%28-2%2B2%29%2B8%28-2-7%29%5D)
= ![\frac{1}{2}[-36+0-72]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B-36%2B0-72%5D)
= 
= (-54) unit²
Therefore, absolute value of the area = 54 square units
(b). Distance between two vertices (a, b) and (c, d)
d = 
AB = 
= 
= 10.295 units
BC = 
= 
= 11.402 units
AC = 
= 12 units
Perimeter of the triangle = AB + BC + AC = 10.295 + 11.402 + 12
= 33.697
≈ 33.7 units
<span>A) 2x=96-14y
B) 9x=40-14y
Rearranging algebraically
</span>
A) 2x <span>+14y = 96
B) 9x </span><span>+14y
= 40</span>
Multiplying equation A by -1
A) -2x <span>-14y = -96 Then adding it to equation B
B) 9x </span><span>+14y
= 40
7x = -56
x = -8
</span><span>2*-8 = 96 -14y
-16 -96 = -14y
-112 = -14y
y = 8
</span>
the problem with this study is the fact that they used precise numbers
hope i helped:)