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3 years ago

A delivery route must include stops at eight cities. how many different routes are possible

1 answer:

5 0

Assuming no limitations on the starting and ending city, then there are 8 choices for the first city, 7 for the second, 6 for the third....
Total number of choices = 8*7*6*...*2*1=8!=40320

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Study these equations:

baherus [9]

Answer:

A. h(x) = 6x2 – 10x – 4

Step-by-step explanation:

Got 100% on edge.

5 0

4 years ago

Read 2 more answers

2. A student had taken six tests and received scores of 88, 73, 81, 83, 79, 94. The seventh test

Veronika [31]

Answer:

a) 83

b) mean and mode are both 83

Step-by-step explanation:

a) mean is the average. so add all the numbers and divide by the number of numbers.

<u>88 + 73 + 81 + 83 + 79 + 94 + T</u> = 83

b) median - put the numbers in numerical order, smallest to largest, what is the middle number (4th number) 73, 79, 81, 83, 83, 88, 94

mode - which number shows up most frequently?

8 0

4 years ago

Find all complex solutions of x^2-5x+7=0

STALIN [3.7K]

Answer:

x1=5/2+i

x2=5/2-i

Step-by-step explanation:

x^2-5x+7=0

a=1, b=-5, c=7

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-(-5)+sqrt(5^2 - 4*1*7))/2

x1=(5+sqrt(25-28))/2

x1=(5+sqrt(-4))/2

x1=(5+sqrt(4i^2))/2

x1=(5+2i)/2

x1=5/2+i

x2=(-b-sqrt(b^2-4ac))/2a

x2=(5-2i)/2

x2=5/2-iw

3 0

4 years ago

I don’t know how to solve this problem. Can someone help

AleksAgata [21]

I think it is e because 39 is not even and 48 isnt odd. then a doesn't intersect b when its not 0? I am not sure. But i am pretty sure it is E.

4 0

3 years ago

How do you do 3k+2k(5k-3)=7 need help due tomorrow !!

rewona [7]

Okay so,
(Heads up! If it’s a number (the one in photo, I don’t know how to type it so imma put a *(number))
3K+2K(5K-3)=7
-
3K+2Kx(5K-3)=7
Multiply parentheses by 2K
-
3K+10K*2-6K=7
Collect the like terms
-
-3K+10K*2=7
Move the constant to the left
-
-3K+10K*2-7=0
Reorder the terms
-
10K*2-3K-7=0
Solve the quadratic equation

6 0

3 years ago