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vichka [17]
3 years ago
15

What the slope of (-6,22)(9,14)​

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

-8/15

Step-by-step explanation:

Do Ysub2-Ysub1/Xsub2-Xsub1

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An ellipse has vertices of (5, 0) and (–5, 0) and covertices of (0, 2) and (0, –2). Use the given information to answer the ques
ValentinkaMS [17]

Answer:

The line the foci will be graphed is?

y=0

The foci are located at about ?

(4.58, 0) and (-4.58, 0)

What type of lines will the directrices be?

Both vertical

The directrices are located at about?

x= 5.46 and x= -5.46

Step-by-step explanation:

7 0
3 years ago
HURRY! I NEED THIS ANSWER FAST!!!!
-BARSIC- [3]
D I did this question a while back
5 0
2 years ago
FIRST ANSWER GETS BRANLIEST
Darina [25.2K]

There are two steps to this problem. The first step is to make an equation for the cost of each company. The cost of each one involves 2 variables. However, we can ignore the number of days since the question asks for per day.

CostA = 90 + .40(miles)

CostB = 30 + .70(miles)

We want to know when A is a better deal or when A costs less. That is when CostA < CostB. We can then substitute the right sides of our equations into the inequality. This will give:

90 + .40(miles) < 30 + .70(miles)     This is where we will now begin to solve for the number of miles.

-30                      -30                       Subtract 30 from both sides.

60 + .4(miles) < .7(miles)                Simplify

      -.4(miles)   -.4(miles)                Subtract .4(miles) from both sides

60 < .3(miles)                                 Simplify

/.3     /.3                                        Divide both sides by .3

200 < miles                                   Simplify

So for A to cost less the number of miles must be greater than 200.

5 0
3 years ago
write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)
gladu [14]
Find midpoint of segment.
(-1,1), (7,-5)
x= \frac{-1+7}{2}=3,y= \frac{1+(-5)}{2}=-2

Find slope of line which passes through (-1,1) and (7,-5).
m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}

The slope of perpendicular line is negative reciprocal value of m.
m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}

Write quation of line which slope is \frac{4}{3} and passes throug the point (3,-2).
m=\frac{4}{3},x_1=3,y_1=-2&#10;\\y-y_1=m(x-x_1)&#10;\\&#10;\\y-(-2)=\frac{4}{3}(x-3)&#10;\\&#10;\\y+2=\frac{4}{3}x-\frac{8}{3}&#10;\\&#10;\\3y+6=4x-8&#10;\\4x-3y-14=0

3 0
3 years ago
8(b+1)=-3(2+b) simply​
gogolik [260]

Step-by-step explanation:

8(b+1)=-3(2+b)

8b+8=-6-3b

8b +3b = -6-8

11b = -14

b = -14/11

8 0
3 years ago
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