Question

Calculate the hydronium ion concentration in an aqueous solution with a ph of 9.85 at 25°c. calculate the hydronium ion concentration in an aqueous solution with a ph of 9.85 at 25°c. 1.4 × 10-10 m 4.2 × 10-10 m 7.1 × 10-5 m 6.5 × 10-5 m 8.7 × 10-10 m

Answer 1

Answer is:  1.4 × 10-10 m
pH = 9.85.
[H₃O⁺] = 10∧(-9.85).
[H₃O⁺] = 1.4·10⁻¹⁰ M.
pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.
If pH is greater than seven, solution is base and if pH is equal seven, solution is neutral and if pH of solution is less than seven, than is acidic.

Answer 2

Answer : The hydronium ion concentration in an aqueous solution is,  $1.41\times 10^{-10}M$

Explanation :  Given,

pH = 9.85

pH : It is defined as the negative logarithm of hydronium or hydrogen ion concentration.

Formula used :

$pH=-\log [H_3O^+]$

Now put the value of pH in this formula, we get:

$9.85=-\log [H_3O^+]$

$[H_3O^+]=1.41\times 10^{-10}M$

Therefore, the hydronium ion concentration in an aqueous solution is,  $1.41\times 10^{-10}M$