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faust18 [17]
2 years ago
13

NO2 + H20-------> HNO2+ HNO3​

Chemistry
1 answer:
Luden [163]2 years ago
8 0

Answer:

6NO2+3H2O-------->3HNO2+3HNO3

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What does a pH of 7 say about a solution?
lisov135 [29]

Answer:

B

Explanation:

it shows that the solution is neutral.

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3 years ago
3. Which type of rock is formed 20 kilometers below Earth's surface? (1 sedimentary 2. metamorphic 3. igneous 4.magma please hel
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3

Explanation:

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A chemical reaction that is expected to form 325.0 gof product only forms 123.8 g of product. What is the percent yield of this
Tasya [4]

Answer:

\boxed {\boxed {\sf A. \ 38.1 \%}}

Explanation:

Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:

\% \ yield = \frac{actual \ yield}{theoretical \ yield} *100

For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.

\% \ yield = \frac{ 123.8 \ g }{325.0 \ g }*100

Divide.

\% \ yield = 0.380923077 *100

\% \ yield = 38.0923077

Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .

\% \ yield \approx 38.1

The percent yield is about <u>38.1%</u>

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2 years ago
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Which of the following is not found in the nucleus of an atom?
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3 years ago
A buffer can be prepared by mixing two solutions. Determine if each of the following mixtures will result in a buffer solution o
GenaCL600 [577]

Answer:

The answers are in the explanation

Explanation:

A buffer is the mixture of a weak acid with its conjugate base or vice versa. Thus:

<em>1)</em> Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. <em>Will </em>result in a buffer because HF is a weak acid and KF is its conjugate base.

<em>2)</em> Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br. <em>Will not </em>result in a buffer because NH₃ is a strong base.

<em>3) </em>Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH. <em>Will </em>result in a buffer because HCN is a weak acid and its reaction with KOH will produce CN⁻ that is its conjugate base.

<em>4)</em> Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl <em>Will not </em>result in a buffer because HCl is a strong acid.

<em>5)</em> Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH <em>Will not </em>result in a buffer because each HCN will react with KOH producing CN⁻, that means that you will have just CN⁻ (Conjugate base) without HCN (Weak acid).

I hope it helps!

6 0
3 years ago
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