Answer: The percent yield of water is 84.72 %
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
For methane:
Given mass of methane= 0.16 g
Molar mass of methane = 16 g/mol
Putting values in equation 1, we get:
For oxygen gas:
Given mass of oxygen gas = 0.25 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction is
By Stoichiometry of the reaction:
2 moles of oxygen gas reacts with 1 mole of methane
So, 0.008 moles of oxygen gas will react with = of methane
As, given amount of methane is more than the required amount. So, it is considered as an excess reagent.
Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of oxygen gas produces = 2 moles of water
So, 0.008 moles of oxygen gas will produce = of water
Mass of water=
To calculate the percentage yield of titanium (IV) chloride, we use the equation:
Experimental yield of water = 0.122
Theoretical yield of water = 0.144 g
Putting values in above equation, we get:
Hence, the percent yield of water is 84.72%.