$f'(x_0)=\lim\limits_{h\to0}\dfrac{f(x_0+h)-f(h)}{h}=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{6}{x};\ x_0=2\\\\subtitute\\\\f'(2)=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-\frac{6}{2}}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-3}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6-3x}{x}}{x-2}=\lim\limits_{x\to 2}\dfrac{6-3x}{x(x-2)}\\\\=\lim\limits_{x\to2}\dfrac{-3(x-2)}{x(x-2)}=\lim\limits_{x\to2}\dfrac{-3}{x}=-\dfrac{3}{2}=-1.5\\\\\\An swer:\boxed{f'(2)=-1.5}$

8 0

2 years ago

HELP PLEASE

Nikolay [14]

Answer:

The 1st the 3rd and 4th are the answers

Step-by-step explanation:

Edgen

4 0

2 years ago

You can work at most 20 hours next week. You need to earn at least $130 to cover your weekly expenses. Your pizza delivery job p

never [62]

P = # of hrs at pizza delivery job, c = # of hrs at car wash job
p + c < = 20 (thats less then or equal)
10.50p + 7.50c > = 130 (thats greater then or equal)

8 0

3 years ago