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fredd [130]
3 years ago
10

SOMEONE PLEASE HELP!!!!

Mathematics
1 answer:
astra-53 [7]3 years ago
3 0
Joint variation equation is a situation when the final value varies by two or more variables

Equation 1

A = s²

Here we have only one variable, 's', and the value of Area will only vary when s varies.

Equation 2

A = πr²

Here the only variable is 'r', which is the radius of a circle. The value of Area, A, varies as radius varies. π is a constant.

Equation 3

A = l×w

Here we have to variables, the 'l' and the 'w'. 
We can say that the value of Area, A, will vary jointly as l and w vary

The correct answer is option a)
You might be interested in
How many ways can you order the digits 2,3,4 and 5. you can only use each number once?
butalik [34]
The number of permutations of the 4 different digits is:
4\times3\times2\times1=24

The answer is 24 ways.
5 0
3 years ago
ASAP PLEASE ASAP PLEASE ASAP PLEASE ASAP PLEASE Ms. Perkins wants to rent a car for a day. It will cost the daily fee of $75 plu
m_a_m_a [10]
Part A would be $75+.$55m and part B would be $165 +$75=$240
7 0
3 years ago
On a coordinate plane, parallelogram R S T U has points (negative 4, 4), (2, 6), (6, 2), and (0, 0). What is the area of paralle
Ad libitum [116K]

Answer:

The area of the parallelogram is;

32 square units

Step-by-step explanation:

The given parameters are;

The coordinates of the parallelogram RSTU = R(-4, 4), S(2, 6), T(6, 2), and U(0, 0)

We note that the area of a parallelogram = Base length × Height

From the drawing of the parallelogram RSTU, we have;

The base length = The length of \overline {TU} = The length of \overline {SR} = √((2 - (-4))² + (6 - 4)²) = 2·√10

The height of a parallelogram is perpendicular to its base length = The line \overline {VT}

∴ Where, the slope of the base length = m, the slope of the height = -1/m

The slope, 'm' of \overline {SR} = (6 - 4)/(2 - (-4)) = 1/3

Therefore, the slope of the height = -1/(1/3) = -3

We note that a point on the height is the point 'T', therefore, the equation of the line in point and slope form is therefore;

y - 0 = -3·(x - 0)

∴ y = -3·x

Therefore, the coordinates of the point 'V' is given by the simultaneous solution of the equations of \overline {SR} and \overline {VT}

The equation of the line \overline {SR} in point and slope form from the point 'R' and the slope 'm = 1/3' is given as follows;

y - 4 = (1/3) × (x - (-4)) = (1/3) × (x + 4)

y = x/3 + 4/3 + 4 = x/3 + 16/3

y = x/3 + 16/3

We then have the coordinate at the point 'V' (x, y) is given as follows;

-3·x = x/3 + 16/3

-9·x = x + 16

-10·x = 16

x = -16/10 = -1.6

x = -1.6

∴ y = -3·x = -3 × -1.6 = -4.8

y = 4.8

The coordinate at the point, V = (-1.6, 4.8)

The length of the line \overline {VT} = The height of the parallelogram = √((-1.6 - 0)² + (4.8 - 0)²) = 8/5·√10

The height of the parallelogram = 8/5·√10

The area of the parallelogram, A = Base length × Height

∴ A = 2·√(10) × 8/5·√(10) = (16/5) × 10 = 32

The area of the parallelogram, A =  32 square units.

6 0
3 years ago
Read 2 more answers
Find the measures of the indicated angle to the nearest degree.​
Nata [24]

Answer:

? = 13.6

Step-by-step explanation:

Let unknown angle be x

so

tan x = p/b

tan x = 8/33

x =tan‐¹(8/33)

or, x = 13.62699486

so, x = 13.6

8 0
3 years ago
What is (4x-3)(7x+6)?
professor190 [17]

Answer:

28x^2+3x-18

Step-by-step explanation:

Formula: (a+b)(a+b) = a^2 + a*b + a*b + b*b

Following this: 28x^2 -21x +24x -18

Then you combine like terms: 28^2 +3x-18

hope this helped!! :)

4 0
3 years ago
Read 2 more answers
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