The fastest way to find the missing endpoint is to determine from the known endpoint to the midpoint and then performing the same transformation on the midpoint.
I'm going to try to let you answer this yourself so you can learn for yourself ok. :3
see the attached figure to better understand the problem
we know that
in the right triangle ABC
cos 56°=AC/AB
where
AC is the adjacent side to angle 56 degrees------> the distance from the surveyor to the building
AB is the hypotenuse-----> 148 ft 2 in
56 degrees------> is the angle of elevation
so
cos 56°=AC/AB---------> solve for AC
AC=AB*cos 56°
AB=148 ft 2 in
convert 2 in to ft
1 ft -----> 12 in
x ft------> 2 in
x=2/12-----> x=0.17 ft
AB=148 ft 2 in-----> 148 ft+0.17 ft------> AB=148.17 ft
AC=AB*cos 56°----> AC=148.17*cos 56°------> AC=82.86 ft
convert 0.86 ft to in
0.86 ft=0.86*12-----> 10.32 in
distance AB=82 ft 10 in
the answer is
the distance from the surveyor to the building is 82 ft 10 in
First simplify like terms (things with the same letter):
3g + 7g + 8 = -10 + g
10g + 8 = -10 + g
Next we should take g off both sides:
9g + 8 = -10
Next isolate 9g by taking 8 off both sides:
9g = -18
Next divide both sides by 9 to find the value of g:
g = -2
Answer:
-48x+16
Step-by-step explanation:
-8(6x - 2) first multiply each term in the parentheses by 8 to get -8x6x-8x(-2) and calculate the product to get your answer which is -48x+16
Answer:
2
Step-by-step explanation:
![f( \frac{1}{4} ) = {16}^{ \frac{1}{4} } = \sqrt[4 ]{16} = 2](https://tex.z-dn.net/?f=f%28%20%5Cfrac%7B1%7D%7B4%7D%20%29%20%3D%20%20%7B16%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%3D%20%20%20%5Csqrt%5B4%20%5D%7B16%7D%20%20%3D%202)
That's it, hope you enjoyed it.