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MariettaO [177]
4 years ago
5

Write an equation in slope intercept form with the given information slope=10 and goes through point (1,5)

Mathematics
1 answer:
avanturin [10]4 years ago
5 0
Y-y1=m(x-x1)
y-5=10(x-1)
Y-5=10x-10
Y=10x-5
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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
sergejj [24]
Slope-intercept form is <em>y</em><em> = </em><em>mx</em> + <em>b</em>, where <em>m</em> is the slope and <em>b</em> is the <em>y</em>-intercept.  To write this in slope-intercept form we must isolate the <em>y</em>:
2x + 3y = 1470
2x + 3y - 2x = 1470 - 2x (subtraction will cancel the positive 2x on the left side of the equation)
3y = -2x + 1470 (since they are not like terms we cannot combine them, we leave them separate)
3y/3 = -2/3x + 1470/3 (cancel the 3 by dividing; EVERYTHING gets divided to keep it equal)
y = -2/3x + 490
The slope of this equation is -2/3 and the <em>y</em>-intercept is 490.
To graph this equation, plot 490 on the <em>y</em>-axis first, since it is the intercept.  Then count over to the right 3 and down 2 to find the next point; continue this for all successive points.
In function notation this would be <em>f</em>(<em>x</em>) = -2/3<em>x</em> + 490.  This function shows how the profit on wrap specials changes as the number of sandwich specials sold increases.  The graph of the function is attached.
The next month, when Sal's profit increased, the function changes because the <em>y</em>-intercept changes.  The slope stays the same.

6 0
3 years ago
How many times doe 4 go in to 37
Ganezh [65]
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4 0
4 years ago
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Solve for x in the equation 2 x squared + 3 x minus 7 = x squared + 5 x + 39.
Nastasia [14]

Answer:

\implies x=1\pm \sqrt{47}

Step-by-step explanation:

We want to solve for x in 2x^2+3x-7=x^2+5x+39

You need to group and combine like terms and write in standard form:

2x^2-x^2+3x-5x-7-39=0

\imples x^2-2x-46=0

By comparing to ax^2+bx+c=0, we a=1,b=-2 and c=-46

The solution can be obtained using the quadratic formula.

x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute the coefficients to get:

x=\frac{--2\pm \sqrt{(-2)^2-4*1*-46} }{2*1}

x=\frac{2\pm \sqrt{4+4*46} }{2}

x=\frac{2\pm \sqrt{4*47} }{2}

x=\frac{2\pm2\sqrt{47} }{2}

\implies x=1\pm \sqrt{47}

The last choice is correct

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3 years ago
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The given series has six terms. what is the sum of the terms of the series? 17 + 25 + 33 + . . . + 57
nikdorinn [45]
Sum of the terms of the series is

Sn = n/2 ( a1+an )

we have n= 6 , a1= 17, an = 57
so Sn = 6/2 ( 17+57) = 3(74) = 222
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Yea. The text book is either wrong or it knows something that we don't. Like as to why they would need to have two more feet. You're right though
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