Answer:
Z: n = 1 P: n =80
Step-by-step explanation:
cross multiple what you can and divide it by the last number left to find n
Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
X-the $5 bills
y-the $10 bills
x+y=20
5x+10y=120
It's a system.
Answer:
The highest score is 94.
Step-by-step explanation:
Let the highest score be denoted by, <em>A</em>, the lowest score be, <em>B</em> and the middle score be <em>X</em>.
Then,
A + X + B = 87 × 3 = 261 ...(i)
X + B = 83.5 × 2 = 167 ...(ii)
⇒ B = 167 - X ...(iii)
A + X = 89 × 2 = 178 ...(iv)
⇒ A = 178 - X ...(v)
Substitute (iii) and (v) in (i) and solve for <em>X</em> as follows:
A + X + B = 261
178 - X + X + 167 - X = 261
345 - X = 261
X = 84
Substitute the value of <em>X</em> in (iii) and solve for B as follows:
B = 167 - X
= 167 - 84
= 83
Substitute the value of <em>X</em> in (v) and solve for A as follows:
A = 178 - X
= 178 - 84
= 94
Thus, the highest score is 94.
Answer:The measure of the arc RPQ is 205°
Step-by-step explanation:
Given the figure in which
m∠ROP=125°
we have to find the measure of the arc RPQ.
As QP is diameter i.e a straight line therefore
∠1 and ∠2 forms a linear pair hence these angles are supplementary.
By supplementary law
∠1+∠2=180°
∠1+125°=180°
∠1=180°-125°=55°
Now we have to find the measure of the arc RPQ i.e
we have to find the measure of ∠2+∠3
By theorem, angles around a point will always add up to 360 degrees.
∴ ∠1+∠2+∠3=360°
55°+∠2+∠3=360°
∠2+∠3=860-55=205°
Hence, the measure of the arc RPQ is 205°
