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MA_775_DIABLO [31]

3 years ago

6

The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is

equal to 20cm?

1 answer:

Afina-wow [57]3 years ago

5 0

Answer:

V＝4/3πr^3；S＝4πr^10；dV/dt＝dV/dr×dr/dt＝4πr^10×dr/dt；dS/dt＝dS/dr×dr/dt＝8πr×dr/dt＝2/r×dV/dt；当r＝10cm时,dS/dt＝50cm^2/s

Step-by-step explanation:

You might be interested in

A student was assigned to read a book over 5 days. On the first day, she read 25 pages. On the second day she read 45 pages, on

nignag [31]

Answer:

Hint : They are a all common factors of 5

Step-by-step explanation:

You divide each of them by 5 then add them all together then you will get your answer.

Good luck!

7 0

2 years ago

If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different

irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0

3 years ago

Find the slope and the y-intercept of the line. 4x-5y=5

Evgen [1.6K]

Answer:

Step-by-step explanation:

4x - 5y= 5

-4x. -4x

-5y = -4x + 5

divide all by -5

y= 4/5x -1

slope is 4/5

y intercept is -1

4 0

3 years ago

Welllllllllllllllllllllllllllllllllllllllllllllllll

VARVARA [1.3K]

Answer:

it izzz what it izzzzz

Step-by-step explanation:

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8 0

3 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

as

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago