1. Shifts up 9
2. Shifts down 2
3. Reflect over x-axis and shifts left 5
4. Shifts right 4 and down 1
5. Vertical compression of 1/3 and shifts up 2
6. Reflect over x-axis, vertical stretch of 2, and shifts left 4
7. f(x)=-(x-3)^2+7
49 degrees would be the correct answer!
Answer:
314 cm³
Step-by-step explanation:
Given ::
Cone height, h = 12 cm
Diameter of cone, d = 10 cm
Hence, radius, r = diameter / 2 = 10/2 = 5cm
The volume of a cone = 1/3 πr²h
V = 1/3 * 3.14 * 5² * 12
V = 3.14 * 25 * 4
V = 314cm³
Answer:
Step-by-step explanation:
Find AOS
X = -b/2a
X = -65/2(-14)
X = -65/-28
X = 2.32 secs
t = 2.32secs
A) y value when t = 2.32 is the maximum height.
Substitute t in the equation.
h(t)= -14t^2+65t+1.75
h(t)= (-14 * 2.32²) + (65 * 2.32) + 1.75
= (-14 * 5.38 ) + (65 * 2.32) + 1.75
= -75.35 + 150.8 + 1.75
= 77.2 ft
Maximum height attained by the ball = 77.2 ft
B) Time the maximum height achieved = 2.32secs
C) The ball off of the ground when it was shot is well t = 0
Substitute t in equation
h(t)= -14t^2+65t+1.75
h(0)= (-14 * 0²) + (65 * 0) + 1.75
= 0 + 0 + 1.75ft
The ball is 1.75ft off the ground when it was shot.
Answer:
-5.7 + (-4.2) is your question and -9.9 should be the answer for you
Step-by-step explanation:
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