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LiRa [457]
3 years ago
12

Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She

obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80 versus Ha:p≠0.80 and calculates a test statistic of 1.10 with a p-value of 0.273. Which of the following best represents the meaning of the p-value?
A: If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273.
B: If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273.
C: If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273.
D: If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273.
E: If the population proportion is 0.80, the probability of observing a sample proportion of at least 0.84 or at most 0.76 is 0.273.
Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Answer:

The correct answer is option (E)

Step-by-step explanation:

Solution to the question

Let us recall from given question that,

H0:p=0.80

Ha:p≠0.80 (which is the two tailed test)

For the p-value we have,

P-value: Let us assume that the null hypothesis is true, then the probability of observing the sample statistics or the  more extreme,

Therefore if p= 0.80, the probability of observing or detecting proportion of samples is of at least 0.84 or at most 0.76 is 0.273.

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Answer:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.1 represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.07 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.01;0;1)", and we got z_{\alpha/2}=2.326, replacing into formula (b) we got:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

3 0
4 years ago
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