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irakobra [83]
3 years ago
14

87% of 70 do not round

Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

60.9

Step-by-step explanation:

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6y+4−3y−7=3(y−1) How many solutions are for this?
Kryger [21]

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Regular + Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

6y + 4 - 3y - 7 = 3(y - 1)

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms:                         3y - 3 = 3(y - 1)
  2. Distribute 3:                                       3y - 3 = 3y - 3
  3. Subtract 3y on both sides:               -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number <em>y</em> and it will render the equation true.

8 0
3 years ago
Read 2 more answers
Solve 3x2 + 4x = 2. TEACH me how to solve this.. I know what to do once I have it in the right forum... but I do not understand
sertanlavr [38]
So if it is 3x^2+4x=2 then
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula x=\frac{-b+ \sqrt{b^2-4ac} }{2a} or  \frac{-b- \sqrt{b^2-4ac} }{2a} so if you were to input it into this equation you would get
a=3
b=4
c=-2

the solution is x= \frac{-2+ \sqrt{10} }{3} or \frac{-2- \sqrt{10} }{3}
the answer is  C
7 0
3 years ago
Read 2 more answers
Answer for any of these will help with work as well
Orlov [11]
13. 81.64
14. 803.84
15. 153.83
16. 753.6


you just use circumference and area formulas for a circle
8 0
4 years ago
I need answers to this
ololo11 [35]

Answer:

x = -5, and y = -6

Step-by-step explanation:

Suppose that we have two equations:

A = B

and

C = D

combining the equations means that we will do:

First we multiply both whole equations by constants:

k*(A = B) ---> k*A = k*B

j*(C = D) ----> j*C = j*D

And then we "add" them:

k*A + j*C = k*B + j*D

Now we have the equations:

-x  - y = 11

4*x - 5*y = 10

We want to add them in a given form that one of the variables cancels, so we can solve it for the other variable.

Then we can take the first equation:

-x  - y = 11

and multiply both sides by 4.

4*(-x - y = 11)

Then we get:

4*(-x - y) = 4*11

-4*x - 4*y = 44

Now we have the two equations:

-4*x - 4*y = 44

4*x - 5*y = 10

(here we can think that we multiplied the second equation by 1, then we have k = 4, and j = 1)

If we add them, we get:

(-4*x - 4*y) + (4*x - 5*y) = 10 + 44

-4*x - 4*y + 4*x - 5*y = 54

-9*y = 54

So we combined the equations and now ended with an equation that is really easy to solve for y.

y = 54/-9 = -6

Now that we know the value of y, we can simply replace it in one of the two equations to get the value of x.

-x - y = 11

-x - (-6) = 11

-x + 6 = 11

-x = 11 -6 = 5

-x = 5

x = -5

Then:

x = -5, and y = -6

5 0
3 years ago
Determine if the relationships are linear and if so are they proportional
Tanzania [10]
Y=2-x^2
Vertex ( 0, 2 )
Focus : ( 0, 7/4 )
Axis of symmetry : x = 0
Directrix : y = 9/4

8 0
2 years ago
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