Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
9 times as many as 3 is 27.
Step-by-step explanation:
It is correct to state that a bit can be in one of 2 states, either 1 or 0.
<h3>What is a bit?</h3>
A bit is is a single binary digit. A bit can either be "1" or "0".
<h3>What is the explanation to the above answer?</h3>
We stated that It is correct to indicate that a bit can be in one of 2 states, either 1 or 0. This indicates that 2ⁿ strings must be created in total. The string must then be processed twice.
- The first time, for generation and
- The second for reading.
Hence, Our time is now O(2ⁿ⁺¹) = O(2ⁿ)
Learn more about bits at;
brainly.com/question/2263640
#SPJ1
Answer:
768
Step-by-step explanation:
because 50 percent of the num is 96 you double that and then multiply by four
Answer:
x=1, x=4
Step-by-step explanation:
