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3 years ago

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A lottery has 60 numbers. To win the jackpot one needs to match all 7 numbers that are drawn by the machine. Is this a PERMUTATI

ON or a COMBINATION problem? What is the “chance” (or, more mathematically speaking, what is the probability) to hit the jackpot?

1 answer:

Vadim26 [7]3 years ago

4 0

Answer: Hence, our required probability is $\dfrac{1}{386206920}$

Step-by-step explanation:

Since we have given that

Numbers in a lottery = 60

Numbers to win the jackpot = 7 numbers

We need to find the probability to hit the jackpot:

So, our required probability is given by

$P=\dfrac{^7C_7}{^{60}C_7}\\\\P=\dfrac{1}{386206920}$

This is a combination problem as we need to select 7 numbers irrespective of any arrangements.

Hence, our required probability is [tex]\dfrac{1}{386206920}[/tex

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svlad2 [7]

Answer:

24) $495

25) 14%

26) 25/X = 83/100

27) 0.7p

28) x + .085x and 1.085x

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31) $6.13

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Step-by-step explanation:

24) 600 - (600 × 0.25) = 450

450 × 1.10 = 495

25) (106 - 93) ÷ 93 = 0.13978

0.13978 × 100 = 13.978 ~ 14

27) 1.0 - 0.3 = 0.7

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3 years ago

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Alinara [238K]

Answer:

a. Not Divisible

b. Divisible

c. Divisible

d. Divisible

e. Divisible

Step-by-step explanation:

To find the divisibility we need to follow the PEMDAS rule and check if the total value can be divided by the selected numbers without returning a remainder.

Let's begin with a:

$16^{5}+215$ by 33

$1,048,576 + 215$

$1,048,791$

We now then divide the total amount with 33.

$\dfrac{1,048,576}{33}$

= 31,781.5454

We can see that the value has a decimal point indicating that the total value divided by 33 will return a remainder. So it is NOT Divisible by 33.

Now let's continue on with the others.

$51^{7}-51^{6}$ by 25

$897,410,677,851 - 17,596,287,801$

$879,814,390,050$

We now then divide the total amount with 25.

$\dfrac{879,814,390,050}{25}$

= 35,192,575,602

The total value did NOT return a decimal point, therefore making the equation true. $51^{7}-51^{6}$ IS divisible by 25.

Next on we have:

$5^{5}-5^{4} +5^{3}$ by 7

$3,125 - 625 + 125$

As we know in the PEMDAS rule, that addition comes first. In this situation we have to read the equation from left to right and solve which ever comes first.

$2,500 + 125$

$2,625$

We now then divide the total amount with 7.

$\dfrac{2,625}{7}$

= 375

The total value did NOT return a decimal point, therefore making the equation true. $5^{5}-5^{4} +5^{3}$ IS divisible by 7.

$7^6+7^5-7^4$ by 11

$117,649+16,807-2,401$

$134,456-2,401$

$132,055$

We now then divide the total amount with 11.

$\dfrac{132,055}{11}$

= 12,005

The total value did NOT return a decimal point, therefore making the equation true. $7^6+7^5-7^4$ IS divisible by 11.

Last but not the least:

$5^{23}-5^{21}$ by 24

$11,920,928,955,078,125-476,837,158,203,125$

$11,444,091,796,875,000$

We now then divide the total amount with 24.

$\dfrac{11,444,091,796,875,000}{24}$

= 476,837,158,203,125

The total value did NOT return a decimal point, therefore making the equation true. $5^{23}-5^{21}$ IS divisible by 24.

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3 years ago

Luba_88 [7]

Answer: No solution

Step-by-step explanation:

The red line is y=3x+7 and the blue line is y=3x+2

The lines do not intersect at any time. Therefore, this set of equations has no solution. I hope this helps! Pls mark brainliest!! :)

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1 year ago