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zhenek [66]
2 years ago
10

Write a matrix to represent the system of equations.

Mathematics
2 answers:
ioda2 years ago
7 0

Answer:

7   -1   6  |  -8

7  -5   7   |  1

0    1    -4 | -5

Step-by-step explanation:

Note that there are four columns in this system, representing the variables x, y and z and constants.  So the given matrix pattern is appropriate:  It has three columns for the coefficients of x, y and z and one column for the constants.

We need only identify the coefficients and transfer them into the appropriate boxes of the matrix pattern.

We get:

7   -1   6   -8

7  -5   7     1

0    1    -4  -5

ozzi2 years ago
5 0

7 - 1 + 6 | 8

7 - 5 + 7 | 1

3 - 4 | -5

mark my answer as brainlist please

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What part of the expression 4(x+3) is a factor
makkiz [27]
4,x,3,and (x+3)
i think
5 0
3 years ago
3. A quadratic polynomial whose<br>product and the sum of<br>zéroes are -12 and 1​
muminat

Answer:

the equation is : x²-x-12

Step-by-step explanation:

the quadratic equation is in the form of : y=ax²+bx+c

the product of the zeros is -12 and the sum is 1

b  = - 1

c=-12 (product)

y=x²-x-12

check : factorize first (x+3)(x-4)=0

either x+3=0 then x=-3

or x-4=0 then x=4

-3*4=-12

-3+4=1

the equation is : x²-x-12

3 0
3 years ago
(a) If the breadth of rectangle in one-third of its length and perimeter is 80 cm, find the length and breadth of rectangle. ​
Gwar [14]

Answer:

Length = 30m and Breadth = 10m  

Step-by-step explanation:  

Given that :  

Perimeter = 80 m ;  

Breadth = 1/3 of Length ; Length = l  

We know that :  

Perimeter of rectangle = 2 ( L + B ).  

80 = 2 ( L + 1/3 L )  

80/2 = 4/3 L.  

40 = 4/3 L  

3/4 × 40 = L.  

3 × 10 = L.  

L = 30m.  

Breadth = 1/3 of Length.  

Breadth = 1/3 × 30.  

Breadth = 10m.

5 0
2 years ago
Read 2 more answers
Does the graph represent a function?<br> just a lil help for khan academy students
cupoosta [38]

Yeah also you got it correct, congrats.

4 0
3 years ago
Hi, can somoene please check why my solution and explain why I get the wrong answer.
trapecia [35]

Answer:

a_n=(1-n)2^n+3^n

Step-by-step explanation:

You are correct down to the part where you add the partial results:

a_n=a_n^h+a_n^p=A3^n+B2^n-n2^n\\\text{Using the given starter values, we can find A, B:}\\a_0=2=A\\a_1=7=3A+2B+2\\\text{has solution A=1, B=1, so ...}\\\\a_n=3^n+2^n-n2^n

4 0
3 years ago
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