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Yuki888 [10]
3 years ago
11

On an average Saturday, 15% of tickets sold are child tickets. If there were 460 tickets sold on Saturday, how many were sold to

children?Equation:___________________
Solution:___________________​
Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

69 is the answer

Step-by-step explanation:

15% of 460 is 69

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a country will produce 3000 missels this year. each of the short range missles costs $200,000 to produce. Each of the medium ran
guapka [62]

Answer:

Step-by-step explanation:

3000/10=300   300=10% of total missiles

300*3=900(30%)   That country (assuming it is Iran) would produce 900 short missiles and 900 medium missiles. 3000-900(2)=3000-1800=1200.

Iran will produce 1200 long range missiles.

For the cost of the missiles,

200,000*900=180,000,000. 300,000*900=270,000,000.

870M-(180M+270M)=870M-450M=420M

420,000,000/1200=350,000.

Long Range Missiles are $350,000 each... got me thinkin bout buying some...

5 0
3 years ago
What is (2/3) to the 4th power?
Wewaii [24]
(\frac{2}{3})^4= \frac{2^4}{3^4}= \boxed{\frac{16}{81}}
8 0
3 years ago
Translate the verbal expression "Five less than the product of X and three" into an algebraic expression
Illusion [34]

Answer:

x+3-5 i think

Step-by-step explanation:

"and" means add so x+3 and subtract 5

6 0
3 years ago
Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean \mu, standard deviation \sigma.

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

8 0
2 years ago
Find I. Choose the right answer. Amount Financed (m) = $1,100 Number of Payments per year (y) = 12 Number of Payments (n) = 18 T
NikAS [45]
B. 10.1%

 (2)(12)($88.18) ÷ [($1100)(18+1)]
        (2,116.32)  ÷ (20,900)
        = 0.1012
        = 10.1%
     
5 0
3 years ago
Read 2 more answers
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