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2 years ago

Parker was able to pay for 44% of his college tuition with his scholarship.

1 answer:

8 0

The total cost is $17,955.

Let x be the total amount of his tuition. He paid for 44% of it, or 0.44, with his scholarship. This leaves 100%-44% = 56% = 0.56 of it to be taken care of with loans. We know he took out 10054.52 in loans:

0.56x = 10054.52

Divide both sides by 0.56:
0.56x/0.56 = 10054.52/0.56
x = 17954.50 ≈ 17955

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Paraphin [41]

The answer would be reading

7 0

2 years ago

Read 2 more answers

F = uv/u + v make u the subject

never [62]

I'm assuming that you mean

$\dfrac{uv}{u+v}$

because if you meant

$\dfrac{uv}{u}+v$

then u would simplify and you couldn't make it the subject.

Under this assumption, we start with

$F=\dfrac{uv}{u+v}$

We multiply both sides by $u+v$

$F(u+v)=uv$

We expand the left hand side:

$Fu+Fv=uv$

We move all terms involving u to the left and all terms not involving u to the right:

$Fu-uv=-Fv$

We factor u on the left hand side:

$u(F-v)=-Fv$

We divide both sides by $F-v$

$u=\dfrac{-Fv}{F-v}$

3 0

3 years ago

A population of caribou in a forest grows at a rate of 6% every year. If there are currently 258 caribou, which function represe

Dimas [21]

Answer:

P(t) = 258( 1 + 6%)^t

Step-by-step explanation:

Given that the population of caribou in a forest grows at a rate of 6% every year. If there are currently 258 caribou, the function representing the number of caribou in the forest in t years will be

P(t) = 258( 1 + 6%)^t

Since it is increasing, it will be 1 + 6%

Where P(t) is the function representing the population after t years.

258 is the current or initial population.

6 0

2 years ago

How can Kendra determine if the function is actually linear?

pashok25 [27]

Answer:

D. She can check to see if the rate of change between the first two ordered pairs is the same as the rate of change between the first and last ordered pairs.

Step-by-step explanation:

Find the rate of change between first two ordered pairs and the second two ordered pairs:

1. Points (2,4) and (3,9). Rate of change:

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{9-4}{3-2}=\dfrac{5}{1}=5$

2. Points (3,9) and (4,16). Rate of change:

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{16-9}{4-3}=\dfrac{7}{1}=7$

The rate of change for the linear function must the same for each two points on the graph of the function. In this case, the reate of change differs, so this function is not linear and correct option is D.

8 0

3 years ago

Read 2 more answers

Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X

timama [110]

Circle A is missing, so i have attached it.

Answer:

∠XYZ = 35°

Step-by-step explanation:

We want to find the angle ∠XYZ in the image attached.

To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;

∠XYZ = ½(arc WZ - arc XZ)