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34kurt
3 years ago
15

A kicker kicks a football toward the opponent's goal line during a game. The ball begins it's flight with an initial velocity of

100 feet per second when it is kicked at a height of 3 feet by the kicker. To the nearest foot, what is the maximum height the ball will reach? Use h(t)=_16t^2+100t+3
Mathematics
2 answers:
Aleks04 [339]3 years ago
6 0

Answer:

Maximum height reached = 159.25 feet

Step-by-step explanation:

We have the equation h(t)=-16t²+100t+3

At maximum height derivative is zero.

That is

        \frac{dh}{dt}=-32t+100=0\\\\t=3.125s

Substituting t = 3.125 s in h(t)=-16t²+100t+3

Maximum height

         h(3.125) = -16 x 3.125²+100 x 3.125 + 3 = 159.25 feet

Maximum height reached = 159.25 feet

Yuri [45]3 years ago
3 0
<span>h=.5*100^2/32+3

Answer: 159 ft.</span>
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