Answer:
9.8
Step-by-step explanation:
Use the distance formula to determine the distance between the two points.

d = distance
= coordinates of the first point
= coordinates of the second point
The solution to the statement 4 + (-4) is correctly given by the third number line.
- The solution given by plot 1 is : (-4) + (-4) as both arrows points 4 units to the left.
- The solution given by plot 2 is : ( 4 + 4) as both arrows points 4 units to the right.
- The solution given by plot 3 is (4) + (-4) as one arrow points 4 units to the left and the other points 4 units to the right.
- The solution given by the plot 4 is (-4 + 8) as one arrow points 4 units to the left and the other points 8 units to the right.
Therefore, the Number line which shows the solution 4 + (-4) is the third number line.
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Answer:
The rule is P(1+r%) power of time (T) so you're gonna apply the number to the rule
Step-by-step explanation:
P=7000
r=1.6%
T=12
7000 x (1+r%) power of T
(1+1.6%) power of 12 = 1.20983040
so when we calculate 7000 x (1+1.6%) power of 12
the answer will be = 8468.812846
So, how far is the car from where it was at t = 0 is 40 m
<h3>Velocity of the car</h3>
Since the location x of the car in meters is given by the function x = 30t - 5t² where t is in seconds, we need to find the time at which its velocity is 10 m/s in the negative direction by differentiating x with respect to t to find its velocity, v.
So, v = dx/dt
= d(30t - 5t²)/dt
= d30t/dt - d5t²/dt
= 30 - 10t
When v is 10 m/s in the negative direction, v = -10 m/s.
So, v = 30 - 10t
-10 = 30 - 10t
-10 - 30 = -10t
-40 = -10t
t = -40/-10
t = 4 s
<h3>The distance at 4 s when its velocity is -10 m/s</h3>
Since at t = 4 s, its velocity is -10 m/s and x = 30t - 5t² is the car's location. The car's distance from t = 0 after its velocity is -10 m/s is
x(4) - x(0) = 30(4) - 5(4)² - [30(0) - 5(0)²]
= 120 - 5(16) - [0 - 0]
= 120 - 80 - 0
= 40 m
So, how far is the car from where it was at t = 0 is 40 m
Learn more about distance of car here:
brainly.com/question/17097458
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